how to perform jump condtion or alternative solution for calling

Suppose I take input at command window through input command

If it is in array then it show that value which was i enter

or if it is not in array then it will jump to take input again..

   N=input('enter the no: ');
   N1=X(N,:)    it will show the coordinate value of N in the array X

Answer 1

[pfb]

Not very clear.

I'm not sure I understand what you want. I'm guessing here.

You have an array X (what's its size?)

Then you ask the user for a number N, presumably an integer.

Then you look up the Nth line of X.

You want to ask for N again if the input value is out of bounds (larger than the number of rows in X). You might also want to make sure that N is an integer.

If this is the case then

 L = size(X,1);
 c = 1; % condition to remain in the loop
 while(c)
    N=input('enter the no: ');
    c = ~((N>0) && (N<L+1) && (N==floor(N)));
    if(c)
      fprintf('no. should be an integer between 1 and %d\n\n',L);
    end

 end

 N1=X(N,:)

[pfb]

Please explain better.

In your example the input number (N) is used as a row index of the matrix X. My code checks whether N is an integer between 1 and the number of rows in X.

What is exactly you want? You say N should be "found in the array". But found where??? Should N appear in the Nth row of X??

[Guillaume]

No idea about what singh is asking, but another option to pfb's code is to actually attempt the indexing and if it fails prompt again:

while true  %loop until we break out of it
   N=input('enter the no: ');
   try
      N1 = X(N, :);  %try indexing
      break;  %if indexing fails, this line will never be executed
   end  %loop around if indexing fails
end