Antworten (2)

VBBV
VBBV am 17 Feb. 2023
Bearbeitet: VBBV am 17 Feb. 2023

1 Stimme

x=1:10; % if you have x as vector of values
2.^(-x) % then use .^ element wise power
ans = 1×10
0.5000 0.2500 0.1250 0.0625 0.0312 0.0156 0.0078 0.0039 0.0020 0.0010
% 2nd option is straightforward
x = 2
x = 2
2^(-x)
ans = 0.2500
%To insert in a given fnction
x = 1:0.1:10;
func = @(x) exp(x)+2.^(-x)+2*cos(x)
func = function_handle with value:
@(x)exp(x)+2.^(-x)+2*cos(x)
plot(func(x))
Fangjun Jiang
Fangjun Jiang am 17 Feb. 2023

0 Stimmen

x=1;
2^(-x)
ans = 0.5000

1 Kommentar

John D'Errico
John D'Errico am 17 Feb. 2023
Bearbeitet: John D'Errico am 17 Feb. 2023
The parens are not technically needed there, but they don't hurt anything.
x = 1;
2^-x
ans = 0.5000
And to be honest, I usually put a parens in something like that myself just to make it easier to read. Sometimes spare parens make things more clear, and sometimes they just create a confusing mess, creating a parenthetical balancing act.

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