How do I print a legend using a character array and integer array?
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Shelley Snider
am 18 Jan. 2023
Kommentiert: Fangjun Jiang
am 19 Jan. 2023
I want to print a legend that looks like this:
1st entry: 'Current solution, 4800 m DR'
2nd entry: 'Current solution, 7000 m DR'
3rd entry: 'Current solution, 9000 m DR'
4th entry: 'Archive solution, 4800 m DR'
5th entry: 'Archive solution, 7000 m DR'
6th entry: 'Archive solution, 9000 m DR'
The numbers come from a structure array. I'm trying to use sprintf, but I'm having troubles with the format of the 'Current' and 'Archive' strings. A character array does not work since sprintf iterates through each character instead of each word. Do I need to do a cell array and then do a comma separated list for that?
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Walter Roberson
am 19 Jan. 2023
A character array does not work since sprintf iterates through each character instead of each word.
A = 'Current'
sprintf('->%s<-', A)
sprintf('->%c<-', A)
You were using the wrong format item.
Akzeptierte Antwort
Stephen23
am 19 Jan. 2023
COMPOSE() is perfect for this, but was first introduced in R2016b. You could use ARRAYFUN() or CELLFUN():
C = {'Current','Current','Current','Archive','Archive','Archive'};
V = [4800,7000,9000,4800,7000,9000];
fnh = @(t,n)sprintf('%s solution, %d m DR',t,n);
lgd = cellfun(fnh,C(:),num2cell(V(:)), 'uni',0)
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Fangjun Jiang
am 18 Jan. 2023
Bearbeitet: Fangjun Jiang
am 18 Jan. 2023
a="current";
b={'archive'};
c='current';
sprintf('%s',a)
sprintf('%s',b{1})
sprintf('%s',c)
2 Kommentare
Fangjun Jiang
am 19 Jan. 2023
Another trick is below, if you put the data in the right format
data={'1st','2nd','3rd';'Current','Archive','Current';4800,7000,9000};
sprintf('%s entry: ''%s solution, %d m DR''\n',data{:})
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