how to make rectangle in circle?

6 Ansichten (letzte 30 Tage)
Sierra
Sierra am 19 Nov. 2022
Kommentiert: Matt J am 20 Nov. 2022
I want to make rectangles in circle.
I know the radius, rectangle's width and length.
please let me know how to do this
thanks
  3 Kommentare
Sierra
Sierra am 20 Nov. 2022
I answerd to Matt J's!
could you guys look at that?

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Matt J
Matt J am 19 Nov. 2022
Bearbeitet: Matt J am 19 Nov. 2022
[X,Y]=ndgrid(-10:10);
r=arrayfun( @(x,y) nsidedpoly(4,'Center',[x,y],'Radius',1/sqrt(2)) , X(:),Y(:));
c=intersect(nsidedpoly(1000,'Radius',5), scale(r,[1,1.5]));
plot(c,'FaceColor','none')
  4 Kommentare
Sierra
Sierra am 20 Nov. 2022
Thanks again.
but My circle's origin point is not zero. so I added my circle's origin point.
width=0.0073;
length=0.0097;
circleRadius=0.0833;
[X,Y]=ndgrid(-circleRadius:width:circleRadius+width);
X(:) = X(:) + ARP_lon % origin x 126.7975
Y(:) = Y(:) + ARP_lat % origin y 37.5569
r=arrayfun( @(x,y) nsidedpoly(4,'Center',[x,y],'Radius',width/sqrt(2)) , X(:),Y(:));
c=intersect(nsidedpoly(1000,'Radius',circleRadius), scale(r,[1,length/width]));
plot(c,'FaceColor','none'); %axis equal
but it didn't work well.
could you explain more?
Matt J
Matt J am 20 Nov. 2022
width=1;
length=1.3;
circleRadius=10;
[X,Y]=ndgrid(-circleRadius:width:circleRadius+width);
r=arrayfun( @(x,y) nsidedpoly(4,'Center',[x,y],'Radius',width/sqrt(2)) , X(:),Y(:));
c=intersect(nsidedpoly(1000,'Radius',circleRadius), scale(r,[1,length/width]));
c=translate(c,ARP_lon,ARP_lat);
plot(c,'FaceColor','none'); axis equal

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Image Analyst
Image Analyst am 19 Nov. 2022
See the FAQ:
Then plot it with plot and then for each x and y value you want find the end points of a line segment and use line() or plot() to draw the line from one side of the circle to the other. It's easy but if you really can't figure it out then write back.
  3 Kommentare
Image Analyst
Image Analyst am 20 Nov. 2022
You do not ned to know the crossing/intersection coordinates of the vertical and horizontal lines inside the circle. All you need to know for the horizontal lines is the y value and the two points on the circle closest to that y value. Similar for the lines in the other direction. But it looks like @Matt J suggested a different approach and you accepted that so I won't proceed with my approach.
Sierra
Sierra am 20 Nov. 2022
Thanks for your answer!

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Geographic Plots finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by