Mode in matlab doesn't work.. can anybody help me with this....?
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Glenn Macion
am 3 Feb. 2015
Kommentiert: John D'Errico
am 26 Feb. 2015
this is my code.. and i'm having a problem running mode for the array i made...
while (1)
userNumber=input('\nPlease enter number:', 's');
if(isempty(userNumber))
break;
end
[myNumber, myStatus] = str2num(userNumber);
if(myStatus == 0 || myNumber < -999999 || myNumber > 999999)
continue;
end
end
fprintf('\n\t\tThe mode of the given set of numbers is:');
x=str2num(myNumber);
MODE=mode(x)
pause;
clc;
1 Kommentar
Akzeptierte Antwort
Stephen23
am 3 Feb. 2015
Bearbeitet: Stephen23
am 3 Feb. 2015
MATLAB's mode works just fine on my computer. Your code was not actually storing any of the values in each loop, and there is also a bit of confusion between string and numeric values. Try this instead:
userNumber = 0;
userVec = [];
while ~isempty(userNumber)
userNumber = sscanf(input('Please enter an integer: ','s'),'%d');
userVec = [userVec,userNumber]; %#ok<AGROW>
end
userVec = userVec(-1e6<userVec & userVec<1e6);
fprintf('The mode of the given set of numbers is %d\n', mode(userVec))
2 Kommentare
John D'Errico
am 26 Feb. 2015
But more than that, as Stephen points out, you cannot take the mode of a string, and have it mean something useful in terms of numbers in that string. For example,
mode('antidisestablishmentarianism')
ans =
i
The mode is the letter i. So I suppose if you are looking for the most common digit in the decimal representation of a number, mode would help there.
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