How to create random matrix with specified step in interval [a, b]
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Reza Lashani
am 22 Mai 2022
Bearbeitet: Reza Lashani
am 23 Mai 2022
Hello everyone. I want to create a matrix with size (m×n) and I want its entities be between 5 and 34 (or in interval [5,34]) with a step of 3. Which means it's only allowed to have 5, 8, 11, 14, ... . How can I create this matrix?
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Voss
am 22 Mai 2022
Bearbeitet: Voss
am 22 Mai 2022
a = 5;
b = 34;
step = 3;
offset = 2;
n_levels = 1+floor((b-a)/step)
% for your reference, showing the min and max
% random values that will be generated:
offset + step*[1 n_levels]
% required size of resulting random matrix:
m = 10;
n = 12;
% generate the matrix using randi,
% [1 n_levels] maps to [5 32]
result = offset + step*randi([1 n_levels],m,n)
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John D'Errico
am 22 Mai 2022
Bearbeitet: John D'Errico
am 22 Mai 2022
You can also use indexing. The idea is to generate random indexes.
ValidRandomSet = 5:3:34
m = 7;
n = 6;
ind = randi(numel(ValidRandomSet),[m,n])
X = ValidRandomSet(ind)
The virtue of such a scheme is it works for any target set of numbers.
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Jonas
am 22 Mai 2022
Bearbeitet: Jonas
am 22 Mai 2022
generate a matrix with random integer values using randi. The spacing will be 1, you can then multiply the values by 3 to get spacing of 3. then shift your values towards your interval by addition
randi(10, 20,30)*3+2
max value will be 32 and minimum value 5
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Image Analyst
am 22 Mai 2022
Here's another way. You can create your random numbers as floating point then use discretize them into numbers in the set you specify:
m = 6
n = 18
% Get the random numbers
r = 5 + (35-5) * rand(m, n)
% Discretize into nearest integer that is in the set
% [5 8 11 14 17 20 23 26 29 32]
edges = 5:3:35
values = edges(1:end-1)
r2 = discretize(r, edges, values)
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