How to use for loop in this problem
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
n=3;
b=eye(n);
b1=b(:,1)
b2=b(:,2)
b3=b(:,3)
2 Kommentare
Stephen23
am 26 Apr. 2022
Bearbeitet: Stephen23
am 26 Apr. 2022
"How to use for loop in this problem"
The main problem I can see is forcing pseudo-indices into variable names. Once beginners start trying to access those variable names dynamically then they force themselves into writing slow, complex, inefficient code trying to access their data:
Basically your bad data design will force you into writing bad code.
What do you think is the problem?
Antworten (1)
chrisw23
am 28 Apr. 2022
Maybe this helps.
tbl = array2table(b);
tbl.b1
tbl.b2
tbl.b3
% see also tbl.Properties
0 Kommentare
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!