How to use for loop in this problem

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하민 김
하민 김 am 26 Apr. 2022
Beantwortet: chrisw23 am 28 Apr. 2022
n=3;
b=eye(n);
b1=b(:,1)
b2=b(:,2)
b3=b(:,3)
  2 Kommentare
Stephen23
Stephen23 am 26 Apr. 2022
Bearbeitet: Stephen23 am 26 Apr. 2022
"How to use for loop in this problem"
The main problem I can see is forcing pseudo-indices into variable names. Once beginners start trying to access those variable names dynamically then they force themselves into writing slow, complex, inefficient code trying to access their data:
Basically your bad data design will force you into writing bad code.
What do you think is the problem?
하민 김
하민 김 am 26 Apr. 2022
thanks for your answer

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chrisw23
chrisw23 am 28 Apr. 2022
Maybe this helps.
tbl = array2table(b);
tbl.b1
tbl.b2
tbl.b3
% see also tbl.Properties

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