How to concatenate string vectors of unequal length?

12 Ansichten (letzte 30 Tage)
Danny
Danny am 20 Dez. 2014
Bearbeitet: Stephen23 am 2 Jan. 2015
If I have thee vectors v1 = {'a' 'b' 'c'}', v2 = {'d'}' and v3 = {'e' 'f'}', how do I create a four vector v4 =
'a' 'd' 'e'
'b' '' 'f'
'c' '' ''
?
  1 Kommentar
Stephen23
Stephen23 am 21 Dez. 2014
Bearbeitet: Stephen23 am 2 Jan. 2015
Actually this is concatenating cell arrays of unequal lengths... the fact that these contain strings is totally irrelevant to both the question and the answer. The title should be "How to concatenate cell vectors of unequal length?"

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Akzeptierte Antwort

Image Analyst
Image Analyst am 20 Dez. 2014
Try this:
% Define component cell arrays.
v1 = {'a'; 'b'; 'c'}
v2 = {'d'}
v3 = {'e'; 'f'}
% Find out how big cell array needs to be.
lv1 = length(v1);
lv2 = length(v2);
lv3 = length(v3);
rows = max([lv1,lv2,lv3])
% Instatiate cell array of the max size.
v4 = cell(rows, 3)
% stuff each column in.
v4(1:lv1, 1) = v1;
v4(1:lv2, 2) = v2;
v4(1:lv3, 3) = v3;
% Print out results
fprintf('\n\nHere is the output cell array:\n');
v4
In the command window:
Here is the output cell array:
v4 =
'a' 'd' 'e'
'b' [] 'f'
'c' [] []

Weitere Antworten (3)

Azzi Abdelmalek
Azzi Abdelmalek am 20 Dez. 2014
v1 = {'a' 'b' 'c'}',
v2 = {'d'}'
v3 = {'e' 'f'}'
v=cell(3,3)
v(:,:)={' '}
v(1:3,1)=v1
v(1,2)=v2
v(1:2,3)=v3

Thorsten
Thorsten am 20 Dez. 2014
v1 = {'a' 'b' 'c'}';
v2 = {'d'}';
v3 = {'e' 'f'}';
m = max([numel(v1) numel(v2) numel(v3)]);
if numel(v1) < m, v1{m} = []; end
if numel(v2) < m, v2{m} = []; end
if numel(v3) < m, v3{m} = []; end
M = [v1 v2' v3]';
X = M(:);

Shoaibur Rahman
Shoaibur Rahman am 20 Dez. 2014
Bearbeitet: Shoaibur Rahman am 20 Dez. 2014
v1 = {'a' 'b' 'c'}';
v2 = {'d'}';
v3 = {'e' 'f'}';
Lv1 = length(v1); Lv2 = length(v2); Lv3 = length(v3);
n = max([Lv1 Lv2 Lv3]);
v1cell = [v1; cell(n-Lv1,1)];
v2cell = [v2; cell(n-Lv2,1)];
v3cell = [v3; cell(n-Lv3,1)];
v4 = [v1cell v2cell v3cell];

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