Hi all, I'm new to MatLab and I copied a function from the website here:
To attempt and solve a problem.
This is my code:
function dc = test(t,c)
k1 = 55.2;
k2 = 30.2;
dc = zeros(3,1);
dc(1) = -k1*c(1)^(1/2)*c(2) - k2*c(3)*c(1)^(1/2);
dc(2) = -k1*c(2)*c(1)^(1/2);
dc(3) = k1*c(2)*c(1)^(1/2) - k2*c(3)*c(1)^(1/2);
options = odeset('RelTol',1e-4,'AbsTol',[1e-4 1e-4 1e-5]);
[T,C] = ode45(@test,[0 1],[0.021 0.0105 0.5],options);
plot(T,C(:,1),'-',T,C(:,2),'-.',T,C(:,3),'.')
The error is:
Error using test (line 5)
Not enough input arguments.
Can anyone help?

3 Kommentare

Rohan Shaju
Rohan Shaju am 27 Mär. 2018
Bearbeitet: Walter Roberson am 28 Mär. 2018
% Simulate supercontinuum generation for parameters similar
% to Fig.3 of Dudley et. al, RMP 78 1135 (2006)
% Written by J.C. Travers, M.H Frosz and J.M. Dudley (2009)
% Please cite this chapter in any publication using this code.
% Updates to this code are available at www.scgbook.info
n = 2^13;                   % number of grid points
twidth = 12.5;              % width of time window [ps]
c = 299792458*1e9/1e12;     % speed of light [nm/ps]
wavelength = 835;           % reference wavelength [nm]
w0 = (2.0*pi*c)/wavelength; % reference frequency [2*pi*THz]
T = linspace(-twidth/2, twidth/2, n); % time grid
% === input pulse
power = 10000;              % peak power of input [W]
t0 = 0.0284;                % duration of input [ps]
A = sqrt(power)*sech(T/t0); % input field [W^(1/2)]
% === fibre parameters
flength = 0.15;             % fibre length [m]
% betas = [beta2, beta3, ...] in units [ps^2/m, ps^3/m ...]
betas = [-11.830e-3, 8.1038e-5, -9.5205e-8, 2.0737e-10, ...
         -5.3943e-13, 1.3486e-15, -2.5495e-18, 3.0524e-21, ...
         -1.7140e-24];
gamma = 0.11;               % nonlinear coefficient [1/W/m]
loss = 0;                   % loss [dB/m]
% === Raman response
fr = 0.18;                  % fractional Raman contribution
tau1 = 0.0122; tau2 = 0.032;
RT = (tau1^2+tau2^2)/tau1/tau2^2*exp(-T/tau2).*sin(T/tau1);
RT(T<0) = 0;          % heaviside step function
%RT = RT/trapz(T,RT);  % normalise RT to unit integral
% === simulation parameters
nsaves = 200;     % number of length steps to save field at
% propagate field
[Z, AT, AW, W] = gnlse(T, A, w0, gamma, betas, loss, ...
                       fr, RT, flength, nsaves);
% === plot output
figure();
lIW = 10*log10(abs(AW).^2); % log scale spectral intensity
mlIW = max(max(lIW));       % max value, for scaling plot
WL = 2*pi*c./W; iis = (WL>400 & WL<1350); % wavelength grid
subplot(1,2,1);             
pcolor(WL(iis), Z, lIW(:,iis)); % plot as pseudocolor map
caxis([mlIW-40.0, mlIW]);  xlim([400,1350]); shading interp; 
xlabel('Wavelength / nm'); ylabel('Distance / m');
lIT = 10*log10(abs(AT).^2); % log scale temporal intensity
mlIT = max(max(lIT));       % max value, for scaling plot
subplot(1,2,2);
pcolor(T, Z, lIT);          % plot as pseudocolor map
caxis([mlIT-40.0, mlIT]);  xlim([-0.5,5]); shading interp;
xlabel('Delay / ps'); ylabel('Distance / m');
Rohan Shaju
Rohan Shaju am 27 Mär. 2018
Please help.Not enough input arguments error!
Walter Roberson
Walter Roberson am 28 Mär. 2018
What is gnlse ?

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 Akzeptierte Antwort

Mischa Kim
Mischa Kim am 23 Nov. 2014

6 Stimmen

Thomson, restructure your code in the following way. Put both functions in the same m-file and save it under the same name as the "main" function, my_ode.m, in this case.
function my_ode()
options = odeset('RelTol',1e-4,'AbsTol',[1e-4 1e-4 1e-5]);
[T,C] = ode45(@test,[0 1],[0.021 0.0105 0.5],options);
plot(T,C(:,1),'-',T,C(:,2),'-.',T,C(:,3),'.')
end
function dc = test(t,c)
k1 = 55.2;
k2 = 30.2;
dc = zeros(3,1);
dc(1) = -k1*c(1)^(1/2)*c(2) - k2*c(3)*c(1)^(1/2);
dc(2) = -k1*c(2)*c(1)^(1/2);
dc(3) = k1*c(2)*c(1)^(1/2) - k2*c(3)*c(1)^(1/2);
end

3 Kommentare

Thomson
Thomson am 23 Nov. 2014
Thank you! This worked :)
Please help.Not enough input arguments error!
function fixedNormal = surfaceNormalImpl(fixedNormal)
% Use 6 neighboring points to estimate a normal vector. You may use
% pcnormals with customized parameter to compute normals upfront
fixed.Normal = surfaceNormalImpl(fixedNormal,idx);
fixedNormal = [fixed.Normal(validPtCloudIndices), ...
fixed.Normal(validPtCloudIndices + fixedCount), ...
fixed.Normal(validPtCloudIndices + fixedCount * 2)];
end
Walter Roberson
Walter Roberson am 27 Mär. 2020
MATLAB thinks you are trying to run the function by itself without passing in any parameters. You cannot just press the green Run button to run that function: you must pass in a single parameter.

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Weitere Antworten (3)

Image Analyst
Image Analyst am 22 Nov. 2014

0 Stimmen

You forgot to include the error message - you just snipped out a tiny part of it and did not tell us the crucial parts. Please read this. And include all the red text (not just part of it, so we'll know what line 5 actually is), and tell us how you called this function, for example what values for t and c did you pass in?
By the way, you didn't just click the green triangle without providing any input arguments whatsoever, did you???

5 Kommentare

Thomson
Thomson am 22 Nov. 2014
Bearbeitet: Thomson am 22 Nov. 2014
Apologies, I did actually try to click the green triangle that is why I'm getting the error. It's late here, however, I am now experiencing a different error:
Attempted to access c(2); index out of bounds because numel(c)=1.
Error in test (line 10)
dc(1) = -k1*c(1)^(1/2)*c(2) - k2*c(3)*c(1)^(1/2);
I just would like to solve the three eqns simutaneously and then graph the result, which should come out to something like this:
If Ch = C(1), Cm = C(2), and Cx = C(3)
Star Strider
Star Strider am 22 Nov. 2014
The code you posted runs for me without error (in R2014b), but gives negative and complex outputs.
There has to be a coding error somewhere. What’s your original system?
Thomson
Thomson am 22 Nov. 2014
Bearbeitet: Thomson am 23 Nov. 2014
I am also running R2014b. My system is as follows.
Image Analyst
Image Analyst am 22 Nov. 2014
What did you pass in for c? Evidently you passed in just a single number, not an array, so there is no c(2) or c(3).
I've tried some vectors such as
[0 0 0]
and now I'm experiencing this error:
Maximum recursion limit of 500 reached. Use set(0,'RecursionLimit',N) to
change the limit. Be aware that exceeding your available stack space can
crash MATLAB and/or your computer.
Error in odeset

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Deeksha kaila
Deeksha kaila am 2 Okt. 2017
Bearbeitet: Walter Roberson am 2 Okt. 2017

0 Stimmen

Hello, I typed a function
Function y=lf(x)
Y=log(1-exp(-1/x))
Bt it displays an error 'Not enough input arguments'. Please help me to run this function.

2 Kommentare

You need to invoke the routine at the command line and pass in a value. For example,
lf(2.334320)
Jan
Jan am 2 Okt. 2017
@Deeksha kaila: Please do not append a new question to an existing thread. This is the section for answers and such "thread hijacking" confuses the readers. Thanks.

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Sowmitha Sangi
Sowmitha Sangi am 29 Nov. 2020

0 Stimmen

function F = SpectralFlux(signal,windowLength, step, fs)
signal = signal / max(abs(signal));
curPos = 1;
L = length(signal);
numOfFrames = floor((L-windowLength)/step) + 1;
H = hamming(windowLength);
m = [0:windowLength-1]';
F = zeros(numOfFrames,1);
for (i=1:numOfFrames)
window = H.*(signal(curPos:curPos+windowLength-1));
FFT = (abs(fft(window,2*windowLength)));
FFT = FFT(1:windowLength);
FFT = FFT / max(FFT);
if (i>1)
F(i) = sum((FFT-FFTprev).^2);
else
F(i) = 0;
end
curPos = curPos + step;
FFTprev = FFT;
end

2 Kommentare

can anyone help me with this :
error: SpectralFlux
Not enough input arguments.
Error in SpectralFlux (line 2)
signal = signal / max(abs(signal));
Walter Roberson
Walter Roberson am 30 Nov. 2020
95% of the time when someone posts something like this, it is because they have pressed the big green Run button to run the code, instead of going down to the command line and invoking the code passing in parameters.
If you press the big green Run button, MATLAB will not look inside the base workspace to find definitions for signal, windowLength, step, or fs: MATLAB relies strictly on the values passed in positionally.

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