How can I check if it is a string?

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Berkin Tan
Berkin Tan am 3 Jan. 2022
Kommentiert: Berkin Tan am 5 Jan. 2022
x = str2double(get(handles.demandValue,'String'));
y = str2double(get(handles.generationValue,'String'));
z = x - y;
set(handles.generationBUS2,'String',num2str(z));
tf = isString(x)
if tf == 1
f = errordlg('Dont write anything except number!','Error!');
return
end
Hi,
I have created a small GUIDE project on my own and I want to check if the user input contains any words and stop the execution. I have tried to write the tf = isStringpart but the tf always returns 0. x and y variables are created on static text.
Thanks.
  2 Kommentare
Matt J
Matt J am 3 Jan. 2022
Because x is the output of str2double(), you know it will always be a double, and therefore it will never be a string.
Berkin Tan
Berkin Tan am 3 Jan. 2022
Thanks.

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Akzeptierte Antwort

Stephen23
Stephen23 am 3 Jan. 2022
Bearbeitet: Stephen23 am 3 Jan. 2022
The simplest approach is to use ISNAN, because STR2DOUBLE will return NaN for any input that it cannot convert to numeric:
if isnan(x) || isnan(y)

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Image Analyst
Image Analyst am 3 Jan. 2022
Try the lettersPattern() function:
pat = lettersPattern creates a pattern that matches text composed of one or more of letters. lettersPattern is Unicode tolerant.
or digitsPattern():
pat = digitsPattern creates a pattern that matches text composed of one or more digit characters. digitsPattern is Unicode tolerant.
Using those (there are other pattern functions by the way), you can determine whether the user entered letters, numerical digits, or a combination of them into the edit text box.

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