A function that counts the number of zeros in a vector

D = ones(1,20);

for i = 1:20;

if mod(i,2) == 0;

D(i) = 0;

end

end

---------

D = [ 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0]

and I need A function that counts the number of zeros in a vector I know there are 10 zeros but how to earn? I found only this but is not enough.

sum(find(D==0)/11) = 10

Answer 1

[Stephen23]

D = [1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0];
nnz(D==0)

ans = 10

Answer 2

[Dave B]

you were pretty close, you just didn't need the find, or the /11

D = [ 1     0     1     0     1     0     1     0     1     0     1  0     1     0     1     0     1     0     1     0]

D = 1×20

1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0

sum(D==0)

ans = 10

Answer 3

[Jan]

Beside

sum(D == 0)
nnz(D)

This would be working also, if the elements are 0 or 1 only:

numel(D) - sum(D)