textscan trouble: starting file position on re-read
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I'm trying to read a data file of integers. The file is formatted as follows:
-112-999-999-999-555
-999-999
-777 0 0 0 0
0 20
-757 11 0 0 0
0 0
There are 3 blocks of 7 numbers each.
I tried
fid=fopen('filename.txt')
textscan(fid,'%4d',7)
And got the following as expected.
-112
-999
-999
-999
-555
-999
-999
But then I issue   textscan(fid,'%4d',7)   again. I would expect to get the second block this time, but instead I get:
2
-999
-999
-999
-555
-999
-999
It seems textscan started reading at the wrong place (not where it left off).
Any thoughts why it's doing this?
Thanks, David
5 Kommentare
Antworten (1)
Image Analyst
am 20 Jun. 2014
In your second call to textscan() your first argument is fww. What is that? Why are you not using fid like in the first call to textscan()????
9 Kommentare
Stephen23
am 10 Okt. 2014
Bearbeitet: Stephen23
am 10 Okt. 2014
Tested with MATLAB R2012b. I downloaded your data file filename.txt, and ran the following code:
>> fid = fopen('filename.txt');
>> A(1) = textscan(fid,'%4d',7);
>> A(2) = textscan(fid,'%4d',7);
>> fclose(fid);
>> [A{:}]
ans =
-100 -106
-101 107
-102 108
-103 0
-555 0
-104 0
-105 20
This seems to give the outputs you want.
per isakson
am 10 Mai 2015
Bearbeitet: per isakson
am 10 Mai 2015
With 2014a
ans =
-100 0
-101 -101
-102 -102
-103 -103
-555 -555
-104 -104
-105 -105
was this ever reported?
Siehe auch
Kategorien
Mehr zu Live Scripts and Functions finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!