textscan trouble: starting file position on re-read

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David C
David C am 19 Jun. 2014
Bearbeitet: per isakson am 10 Mai 2015
I'm trying to read a data file of integers. The file is formatted as follows:
-112-999-999-999-555
-999-999
-777 0 0 0 0
0 20
-757 11 0 0 0
0 0
There are 3 blocks of 7 numbers each.
I tried
fid=fopen('filename.txt')
textscan(fid,'%4d',7)
And got the following as expected.
-112
-999
-999
-999
-555
-999
-999
But then I issue &nbsp textscan(fid,'%4d',7) &nbsp again. I would expect to get the second block this time, but instead I get:
2
-999
-999
-999
-555
-999
-999
It seems textscan started reading at the wrong place (not where it left off).
Any thoughts why it's doing this?
Thanks, David
  5 Kommentare
Patrick
Patrick am 9 Okt. 2014
I ran into this same issue with R2013b.

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Antworten (1)

Image Analyst
Image Analyst am 20 Jun. 2014
In your second call to textscan() your first argument is fww. What is that? Why are you not using fid like in the first call to textscan()????
  9 Kommentare
Stephen23
Stephen23 am 10 Okt. 2014
Bearbeitet: Stephen23 am 10 Okt. 2014
Tested with MATLAB R2012b. I downloaded your data file filename.txt, and ran the following code:
>> fid = fopen('filename.txt');
>> A(1) = textscan(fid,'%4d',7);
>> A(2) = textscan(fid,'%4d',7);
>> fclose(fid);
>> [A{:}]
ans =
-100 -106
-101 107
-102 108
-103 0
-555 0
-104 0
-105 20
This seems to give the outputs you want.
per isakson
per isakson am 10 Mai 2015
Bearbeitet: per isakson am 10 Mai 2015
With 2014a
ans =
-100 0
-101 -101
-102 -102
-103 -103
-555 -555
-104 -104
-105 -105
was this ever reported?

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