String value and sequently representation

Lets say i have string

M=['XASSANORXOOUOU']

and I want something like this

for i=1:7
Li=[M(i,i+1)]

so that it would give me like this result:

L1=XA
L2=SS
L3=AN
L4=OR

and so on....but this code

Li=[M(i,i+1)]

is not working. Could u help me please.

[John D'Errico]

Please learn how to put your code in code blocks, as it was unreadable otherwise.

[Akmyrat]

yes John, that is the problem for now i can not do it in proper way, i tried this for i=1:7 L=M(2*i,2*i-1) end % but this gives like that answer L=XA, L=SS, L=AN...and so on. but i want it like this L1=XA, L2=SS, L3=AN...

[Image Analyst]

Try this: http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup

Answer 1

[Geoff Hayes]

M is a matrix with a single row, so the code cannot access anything but that first row. As soon as i is greater than 1, then M(i,i+1) will fail with an index out of bounds exception. If you just want to get the pairs, then try something like:

 for i=1:2:length(M)   % since we are interested in the odd indices only
   str = M(i:i+1);     % get the two neighbouring characters
 end

If you want to print out something like you have above, then just replace the middle line with

 fprintf('L%d=%s\n',floor(i/2)+1,M(i:i+1));

If you are trying to save the values at each iteration to a variable named Li then that gets a little more challenging (is it even necessary?).

[Akmyrat]

thanks a lot Geoff, it works...yes it is necessary :)

Answer 2

[rifat]

M=['XASSANORXOOUOU'];

for i=1:length(M)/2
    string=['L' num2str(i) '=M(2*(i-1)+1:2*i)']
    eval(string)
end