function Ml = myseries(t)
n=0;
while (n<10)
Ml = sum(t.^n/(gamma(n + 1)));
n = n+1;
end
The above code runs well as long as the input variable is a scalar; for vectorized inputs, it fails. What might be wrong?

4 Kommentare

Azzi Abdelmalek
Azzi Abdelmalek am 21 Dez. 2013
What "It fails" means? is there any error message?
John D'Errico
John D'Errico am 22 Dez. 2013
It isn't a question of MAKING it accept vector input. ANY function can always accept vector inputs. The issue is your code, making it work with vectors.
Ben
Ben am 29 Mär. 2017
sum(t.^n/(gamma(n + 1))) needs to have a . before the /
Walter Roberson
Walter Roberson am 29 Mär. 2017
./ would only be needed if the right hand side, gamma(n+1) was a vector or matrix, but in this context it is a scalar.

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 Akzeptierte Antwort

Youssef  Khmou
Youssef Khmou am 21 Dez. 2013

1 Stimme

You did not specify how the output should be , 1x1 or Nx1 , you can try this way :
function Ml = myseries(t)
n=0;
ctr=1;
while (n<10)
Ml(ctr) = sum(t.^n/(gamma(n + 1)));
n = n+1;
ctr=ctr+1;
end

Weitere Antworten (2)

Walter Roberson
Walter Roberson am 21 Dez. 2013

1 Stimme

Your current code overwrites all of Ml each time through the "while" loop, and so is unlikely to be doing what you want.
for n = 0 : 9
Ml(n,:) = sum(t.^n/(gamma(n + 1)));
end

4 Kommentare

Error Message: ??? Subscript indices must either be real positive integers or logicals.
Youssef  Khmou
Youssef Khmou am 21 Dez. 2013
Just a small correction, @Walter, the index must start at 1.
Right, sorry,
for n = 0 : 9
Ml(n+1,:) = sum(t.^n/(gamma(n + 1)));
end
I am proud to belong to this community; you all are legends. Many thanks

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Image Analyst
Image Analyst am 21 Dez. 2013
Bearbeitet: Image Analyst am 21 Dez. 2013

1 Stimme

I think you can to what you want to do with one of these functions. Not sure what you want to do so pick one:
function theSum = myseries(t)
% Vectorized method.
n = 1:length(t);
theSum = sum(t.^n ./ (gamma(n + 1)));
function theSum = myseries(t)
% For loop method.
theSum = 0;
for n = 1 : length(t)
theSum = theSum + t(n)^n ./ gamma(n + 1);
end
This does something completely different than the other two answers but I think is what you were actually intending, which is trying to sum a series.

5 Kommentare

Youssef  Khmou
Youssef Khmou am 21 Dez. 2013
i think the output should be a vector , if it was not the case, then a simple "sum(.....)" should suffice .
Image Analyst
Image Analyst am 22 Dez. 2013
I'm not so sure. It looks like he's trying to sum a series, and that would give a single summed value. I think he wants the sum of the first 10 terms of t(n)^n/gamma(n+1). A 10 element array t is passed in and n goes from 1 to 10. At least that's how I interpret it. Why do you think he wants a vector?
Youssef  Khmou
Youssef Khmou am 23 Dez. 2013
it is guess, like i explained, if it was not a vector, no need for a question, a simple "sum(quantity)" is fine .
Image Analyst
Image Analyst am 23 Dez. 2013
Well he accepted your interpretation so I guess you were right. The Ml(2) was the sum of terms 1 and 2, the Ml(3) was the sum of terms 1, 2, and 3, and the element Ml(N) was term1 + term2 + term3 + term4 +....+termN. I thought he wanted just one sum - the sum of terms 1 through term N - not N sums, but I guess I was wrong.
Youssef  Khmou
Youssef Khmou am 23 Dez. 2013
ok

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