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Error using horzcat Dimensions of matrices being concatenated are not consistent.
Signal=[zeros(1,((Lmax-SignalLength-1)/2)),(Obj.CompCellList{CellNr}{iFrame}.(signal)),zeros(1,((Lmax-SignalLength+1)/2))]; I...

5 Tage ago | 1 answer | 0

1

answer

Question


How to plot Z vs Y from a data matrix X,Y,Z as line plots for specific X values on separate figures?
I want to get X number of figures with Z vs Y plots. for i=0:numel(X) fig(i)=fig...

11 Tage ago | 0 answers | 0

0

answers

Question


How to find length of a field of an object?
I have an object that contains signal values. I want to find the length of the signal inbetween two elements in the field called...

7 Monate ago | 0 answers | 0

0

answers

Question


What is the meaning of this code snippet?
function Average(Obj,signal,AnalysisType,TimePoints,varargin) if nargin==3 Ex...

8 Monate ago | 1 answer | 0

1

answer

Question


How can I create a matrix with matrix elements of different datatypes?
I want to make a nx2 matrix in which the first column consists of integers but the second column consists of a structure. Someth...

11 Monate ago | 1 answer | 0

1

answer

Question


Error using lsqncommon (line 67)
I am trying to fit heat maps from biological cells. My code works for most of my cells but a few cells failed due to incorrect f...

12 Monate ago | 0 answers | 0

0

answers

Solved


Pizza!
Given a circular pizza with radius _z_ and thickness _a_, return the pizza's volume. [ _z_ is first input argument.] Non-scor...

etwa ein Jahr ago

Solved


Times 2 - START HERE
Try out this test problem first. Given the variable x as your input, multiply it by two and put the result in y. Examples:...

etwa ein Jahr ago

Question


Error using length, Too many input arguments.
I have a bunch of data from animal cells at different times. j represents the time frame. I want to extract a field from my obje...

etwa ein Jahr ago | 2 answers | 1

2

answers

Question


Extract data using ginput and fit with a formula of your choice
I am choosing two end points using ginput [x,y] = ginput(2) and then I need to separate my data set which lies between the two e...

mehr als ein Jahr ago | 1 answer | 0

1

answer