"Non-scored bonus question: Why is the function interesting?"
- Because the question is in the answer, as long as you do not go for the shortest one.

You can calculate the most value for your money!

This made me laugh more than I care to admit...

Awesome. FWIW, I call foul on the solutions that use Neural Network toolbox - isn't Cody supposed to not use toolboxes?

Why is the function interesting ?
pi_z_z_a ... that's why ... :D

Lol, very nicely done :)

Definitely one of my favorites ;)

PIZZA!!

Kawabanga

You genious :)

Very funny problem with a tasty solution!

made me smile

ha ha ha, soooo funny

Classic!

:)

Nicely apt answer :)

:)

Nice one! I need to go buy the shirt now.

bit tricky

Well served!

Lol that's hilarious... the volume is two pies

pi*z*z*a

Because y = pi*z*z*a

y = pi*z*z*a

pi*z*z*a

y= pi*z*z*a

y = pi*z*z*a

y = pi*z*z*a

y=pi*z*z*a

y = pi*z*z*a

pi*z*z*a

pi*z*z*a!

Nice question! :)

y=pi*z*z*a

y=pi*z*z*a (:

pi*z*z*a

y = pi*z*z*a

V = pi*z*z*a

v=pi*z^2*a

ans = pi*z*z*a

V = pi*z*z*a

y = pi*z*z*a

because the question does not ask for a formula

A = pi*z*z*a

pi*z*z*a

the volume is equal to: pi*z*z*a

ans= pi*z*z*a

pizza = pi*z*z*a

ans= pi*z*z*a

ans= pi*z*z*a

pi*z^2*a

ans= pi*z*z*a

ans= pi*z*z*a

pi*z*z*a

pi*z*z*a

I didn't get what should I insert there to solve it. Could anybody send me the guidelines to dos_lp | at | mail dot ru
Thanks you!

volume = pi .* z .* z .* a;

pi*z*z*a

volume = pi .* z .* z .* a

volume = pi .* z .* z .* a;

why is my solution wrong?

function y = pizza(z,a)
y = pi*z*z*a
end

y = pi*z*z*a

Usually I get the following response:

"No public property version exists for class cody.verifyCode."

but about the tenth time it finally worked.

Not sure what the issue is but it usually bombs on both MS Edge and Chrome browsers.

ti's ok... y = pi*z*z*a; %

pi*z*z*a

v = pi*z*z*a

pi*z*z*a

pi*z*z*a

pi*z*z*a

pi*zz*a

pi*z*z*a

ans=pi*z*z*a

pi*z*z*a

ans=pi*z*z*a

ans=pi*z*z*a

Volume= pi*z*z*a

ans=pi*z*z*a

ans=pi*z*z*a

Volume= pi*z*z*a :)

ans= Pi*z*z*a

A=Pi*z*z*a

How about z*a*a*pi?

Volume = Pi*z*z*a

Volume = Pi*z*z*a

pi*z*z*a!

syms a, z
volume=pi*z^2*a

pi*z*z*a

V_pizza = Pi*z^2*a;

ans=pi*z*z*a

For Pizzas give one = get one

ans=
pi*z^2*a

pizza

Pizza

pi*(z*z)*a

nom nom :)

pizza

Pizza = pi*z*z*a
-_-

Volume = pi * (z*z)*a

F(z) = pi*(z^2)*a;

pizza=pi*z*z*a.............

pi*z*z*a

ans = pi*z*z*a

pi*z*z*a

pi*z*z*a

delicious= pi*z*z*a;

pi*z*z*a

z*z*a*Pi

z = 1;
a = 1;
v_correct = pi;
assert(isequal(pizza(z,a),v_correct))

pi.z.z.a

Interesting :)

pi*z*z*z

Volume = pi*z*z*a;

pi*z*z*a

Volume = pi*z*z*a

I want some pi*z*z*a

Pi*z*z*a

function [Volume] = findVolume(r,h)
input(radius of pizza is: );
input(thickness of pizza is: );
Volume = pi*r*r*h;
end
% The output "produce" pizza, which got me salivating.

this should be an awesome pi*z*z*a

pi*z*z*a :D

pi*z*z*a :D

V = a*\pi*z^{2}

pi*z*z*a

pi*z*z*a!

pi*z*z*a

pi*z*z*a

pi*z*z*a

F(z)=pi*z*z*a

F(z)=pi*z*z*a

pi*z*z*a

F(z)=pi*z*z*a

pi*z*z*a

pi*z*z*a

Volumeofpizza = pi*z*z*a %This is the volume of a cyclinder (pi*r^2*a)

pi*z*z*a

It's interesting because pi is in pizza and pi*r^2*h is the volume of a cylinder. In this case we are assigning the radius of the pizza with z and the height with a!

pi*z*z*a*
Yummmmm

pizza......nice work!

I am very interested in this Problem.

solution pi*z*z*a

Oww, it is best ...

y=pi*z*z*a

pizza

pi*z*z*a*

pi*z*z*a*

volume = pi*z*z*a

Pi*z*z*a

V = pi*z*z*a

pi*z*z*a

V = pi*z*z*a

V=pi*z*z*a;
*hoho*

V = pi*z*z*a

Could be p*i*z*z*a factorial? (Pizza!)

pizza = pi*z*z*a

I thing that
F = (pi)*(z^2)*a

ans=pi*z*z*a

F = (pi)*(z^2)*a

Pi*zz*a

It is fun as the answer is itself!

%Answer :
function volume = funpizza(z,a)
volume = pi*z*z*a;
end

%Answer:
function volume = funpizza(z,a)
volume = pi*z*z*a;
end

function volume = pizza_volume(z,a) ;
volume = pi*z*z*a;
return;

p*i*z*z*a

function vol = piz(z,a) vol = pi*z*z*a; end

pi*z*z*a!!!

pi*z*z*a

radius=z
th=a
volume=pi*z*z*a

where is my pi*z*z*a

v=pi*z*z*a

ans = pi * z * z * a;

pi*z*z*a

It is fun!

pi*z*z*a

ans= pi*z*z*a

"Pizza!"

pi*z*z*a

ans= pi*z*z*a

Pi*z*z*a

pi*z*z*a

ans = pi * z * z * a

pi * z * z * a

pi*z*z*a

I'm really interested in knowing how to reduce the size of my answer (18).

pi*z*z*a it should be

pi*z*z*a

Pi*z*z*a

pi*z*z*a as it is circular thus, pi*r*r is the area and a is the height/thickness.

pi*z*z*a

F(z)=pi*(z^2)*a;

pi*z*z*a

pi*z*z*a

pi*z*z*a

pi*z*z*a

V = pi*z*z*a

function [V] = pizza(z,a)
V = pi*z*z*a;
end

V = pi*z*z*a

volume = pi*z*z*a;

V=pi*z*z*a

ans = pi*z*z*a

pi*z*z*a

V = pi*z*z*a

ans = pi*(z^2)*a

pi*z^2*a

ans = pi * z * z * a

z = input('Enter the radius of a pizza: ');
a = input('Enter the thickness of a pizza: ');

V=pi*z*z*a

3.14*ztrans(ztrans(a))

ans = pi * z * z * a

V=pi*z*z*a

y = pi*z*z*a

ans = pi*z*z*a

V = pi .* (z .^ 2) .* a;

Volume = pi * z * z * a

ans = pi*z*z*a ..........hahhahahha

Answer:
R=z;
H=a;
V=pi*(R^2)*H;

V = pi .* (z .^ 2) .* a;

V=pi*z^2*a

V=pi*z*z*a

V=pi*z*z*a;

V=pi*z^2*a

V=pi*z*z*a

funtction [V] = pizza_volume(z,a)
V=pi*z^2*a;
end

Funny!!!

y=pi*z^2*a

y= pi*z^2*a

V = pi*z*z*a

y=pi*z^2*a

indeed.

Easy

this's funny

easy

i like these basic questions, they dont really require you to go through the manuals and basic.

interesting question

yay

so i need a piz2a now

good one

nice

nice

Pretty tricky and funny. haha, XD

lol very easy

:)

That was a tough one

nice

My favorite food is pi*z*z*a

Very funny problem!

nice

volum=f(z,a)=(pi*z^2*a)

Tasty solution!!

Pizza!

Just trying to get points...

Doing this for a grade in class.

(Y)

ha ha ha. r become z and h become a.

Very simple and useful example.

great problem!

Haha! Good one!

how to reduce size from 18 to 10?

Nice!!

Just love this one:)

pizza pi! Yum

Took me time to get the joke, since I started with a rounded edge pizza instead of a cylinder.

I got:
Volume = (a*pi*((a/2 - z)^2 + 2*z^2))/3

Technically more accurate, but clearly not as funny as the intended result...

(I suck at math so I had to Google the volume of a barrel shape, and constrain it to : rounding radius = thickness/2, and let the solve function do the algebra for me...)