# Anastasia Kyriakou

Last seen: mehr als 3 Jahre vor Aktiv seit 2020

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I have collected some real assets and i have calculated the rate of return of those. I have to do portfolio optimization by mini...

mehr als 3 Jahre vor | 1 Antwort | 0

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Help for a function which works like triu function in matlab
we have seen the function triu(A,k) which extracts upper triangular part of A. But i have to write my own function with the head...

mehr als 4 Jahre vor | 1 Antwort | 0

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Triu function in matlab programming
Matlab has a function triu(A,k) which extracts upper triangular part of A.Write your own function with the header U = myTriu(A,k...

mehr als 4 Jahre vor | 0 Antworten | 0

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Plotting 3 graphs in the same figure
Write a programme to plot the function f(x)=xsin(pi(9x+1)) over the interval [−1, 1] using increments in x of (a) 0.2, (b) 0.1, ...

mehr als 4 Jahre vor | 1 Antwort | 0

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Error in a code which computes sqrt(a)
One of the methods to compute sqer (a) , a>0 is X(n+1) = (a + (X(n)*X(n-1))/(X(n)+X(n-1)), n = 1, 2, …, with X0=1 and X1=a (T...

mehr als 4 Jahre vor | 1 Antwort | 0

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algorithm for computing ? is due to Archimedes: how steps can be repeated
The following algorithm for computing ? is due to Archimedes: 1. Start with ? = 1 and ? = 6. 2. Replace ? by 2?. 3. Replace ?...

mehr als 4 Jahre vor | 1 Antwort | 0

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Explicit Euler integration. Plot x(t) and y(t)
I have this exercise: dx/dt = −x(1 − y), t0 = 0, x(t0) = 0.5, dy/dt = y(1 − x), t0 = 0, y(t0) = 2 These equations ...

mehr als 4 Jahre vor | 0 Antworten | 0

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improved Euler integration scheme (possible code error) in matlab
I have this ex: dx/dt = −x(1 − y), t0 = 0, x(t0) = 0.5, (3) dy/dt = y(1 − x), t0 = 0, y(t0) = 2 (4) These equations are als...

mehr als 4 Jahre vor | 1 Antwort | 0

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Matlab: a function y where y is the ?-th Chebyshev polynomial of the first kind evaluated at xy is the ?-th Chebyshev polynomial of the first kind evaluated at xy is the ?-th Chebyshev polynomial of the first k
Chebyshev polynomials of the first kind, ?n(?), are defined recursively as follows: ?0(?) = 1, ?1(?) = ?, and ??(?) = 2???−1(?) ...

mehr als 4 Jahre vor | 1 Antwort | 0

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