test case 2 is incorrect. the given function will only return positive values, which means it is not equivalent to sin (and therefore new wine)
adding 'for positive inputs between 0.2 to 0.8'
In terms of Matlab's numerical accuracy, @(z)log10(10*z)-1 is not equal to log10. Therefore, it is new wine, as it produces different results than the built-in function.
I don't understand this problem.
Whether the input is vector?
Reindex a vector
Determine if input is a perfect number
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