Problem 403. Einsteinium-253 decay

Created by Bruce Raine

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?><w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Radioactive Einsteinium-253 has a half-life of 1,768,608 seconds. Given 1000mg of Einsteinium-253 at t=0 days, how much is left after 50 days?</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>EX: >> decay(50)</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>184</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>HINT: find k, then decay(50)</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>Use: decay(t)=10^3*e^(k*t)</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>NB: make sure you round your answer up to the next highest integer.</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Solve

Solution Stats

297 Solutions
106 Solvers

Last Solution submitted on Apr 28, 2023

Last 200 Solutions

Problem Comments

5 Comments

5 Comments

Show 2 older comments

Alfonso Nieto-Castanon on 25 Feb 2012

guess you mean minutes instead of seconds?

Bruce Raine on 25 Feb 2012

Hi, no I do mean seconds if you are referring to the constant, 29,476.8

Bruce Raine on 25 Feb 2012

I have readjusted it now so it is the correct value.

Rick Rosson on 25 Feb 2012

I believe you are always rounding up to the next highest integer rather than rounding to the nearest integer. In other words, you are using the ceil() function, not the round() function.

Bruce Raine on 25 Feb 2012

Hi Rick, yes you are quite right. I have made the correction as above. Thanks for your valuable input.

Solution Comments

Show comments

Problem Recent Solvers106

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Problem 403. Einsteinium-253 decay

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers106

Suggested Problems

More from this Author16

Problem Tags

Community Treasure Hunt

Problem 403. Einsteinium-253 decay

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers106

Suggested Problems

More from this Author16

Problem Tags

Community Treasure Hunt

Players