Is there a function that retrieves the filename of the current script?

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Is there a way to, from a .m file, determine the filename (including directory path) of that .m file?

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 20 Jun. 2011
S = dbstack();
S(1).file
You might have to use the -completenames option.
  5 Kommentare
Kevin  Hartman
Kevin Hartman am 13 Mär. 2021
Additionally, S(1).name in the above example returns the filename sans extension c. MATLAB 2020b

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Weitere Antworten (3)

Kaustubha Govind
Kaustubha Govind am 20 Jun. 2011
p = mfilename('fullpath')
  3 Kommentare
Walter Roberson
Walter Roberson am 20 Jun. 2011
mfilename does not include the extension, and thus cannot distinguish between .p and .m files.
mfilename without any option does not include the path as was specifically requested by the user.

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Eric LePage
Eric LePage am 23 Okt. 2019
I'd appreciate a qualification, because what I get for R2019b is not very helpful; it certainly isn't the name of the currently running mfile. Thanks.
P = mfilename
P =
'LiveEditorEvaluationHelperESectionEval67edf31d'
or
S = dbstack();
>> S(1).file
ans =
'LiveEditorEvaluationHelperESectionEval67edf31d.mlx'
  8 Kommentare
Rik
Rik am 24 Okt. 2022
@Chris Jennings You can strip the path away with the fileparts function:
[FullPath,Filename,ext]=fileparts(matlab.desktop.editor.getActiveFilename)

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Martin Koch
Martin Koch am 23 Okt. 2022
With the Path class you can get the file path with
Path.this
and the parent directory with
Path.here
Use the string method to convert to a string if needed:
Path.this.string
Disclaimer: I'm the author.

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