Joining label

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Mohammad Golam Kibria
Mohammad Golam Kibria am 19 Jun. 2011
Hi I have the following matrix
I =
0 1 0 0 1 0
0 0 0 1 0 0
0 0 0 0 0 0
0 0 1 1 0 0
0 1 0 0 1 0
1 0 0 0 0 1
and
L=bwlabel(I)
L =
0 2 0 0 3 0
0 0 0 3 0 0
0 0 0 0 0 0
0 0 1 1 0 0
0 1 0 0 1 0
1 0 0 0 0 1
I need to join or merge those label who have minimum distance 2. Is there any one to help?
  1 Kommentar
Mohammad Golam Kibria
Mohammad Golam Kibria am 20 Jun. 2011
label 1 and label 3 are in minimum distance 2 but label 2 is not within minimum distance 2 with any of label 1 or 3.
the out put might be like bellow:
0 2 0 0 1 0
0 0 0 1 0 0
0 0 0 1 0 0
0 0 1 1 0 0
0 1 0 0 1 0
1 0 0 0 0 1

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Antworten (3)

Jan
Jan am 19 Jun. 2011
To join the regions, exapand them at first. I assume "minimum distance of 2" means a dilation with a 3x3 matrix:
I = [0 1 0 0 1 0; ...
0 0 0 1 0 0; ...
0 0 0 0 0 0; ...
0 0 1 1 0 0; ...
0 1 0 0 1 0; ...
1 0 0 0 0 1];
I2 = imdilate(I, ones(3, 3));
L = bwlabel(I2);
% Now remove all points, which are 0 in the original matrix:
L(I == 0) = 0;

the cyclist
the cyclist am 19 Jun. 2011
It is not clear to me what you mean by "join or merge". Perhaps you can tell us what the correct output is for the example you have given?
The find() command might be part of what you need. For example,
>> [i,j] = find(L>=2);
will give you the (i,j) coordinates of the values of L greater than or equal to 2.

Andrei Bobrov
Andrei Bobrov am 19 Jun. 2011
C = nchoosek(1:max(L(:)),2);
[ii jj c] = arrayfun(@(i1)find(bwdist(L==C(i1,1)).*(L==C(i1,2))),1:size(C,1),'un',0);
leq = C(cellfun(@(x)min(x),c)<=2,:);
for jj = 1:size(leq,1),
leq(ismember(leq(:,1),leq(jj,2)),1) = leq(jj,1);
L(L==leq(jj,2)) = leq(jj,1);
end
CORRECTED
I1 = I;
L = bwlabel(I1);
for ii = max(L(:)):-1:1
c{ii} = bwdist(L==ii)==1;
end
I1(sum(cat(3,c{:}),3) > 1)=1
Lnew = bwlabel(I1)

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