# Sorting an array with if, for and while loop only.

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Rishabh Chaudhary on 13 Aug 2021
Commented: Jan on 7 Sep 2021
I have an array A and I want array B as result using only if, for and while loops (no in-built function).
A = [0 1 2 3 4 5 0 6 7 8 0 9 10 11 0 12 13 ]
B= [ 0 1 2 3 4 5 0 -6 -7 -8 0 9 10 11 0 -12 -13]
##### 3 CommentsShowHide 2 older comments
Jan on 7 Sep 2021
The vector B is not sorted, especially not a sorted version of vector A.
Maybe B is a copy of A where the sign in changed whenever a 0 occurs. Before you can implement this in code, you have to define exactly, what you want to achieve.

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### Answers (1)

Sreedhar Arumugam on 7 Sep 2021
There are many sorting algorithms that can be used to answer your question.
As a starter, I would recommend learning Bubble Sort which works by repeatedly swapping adjacent elements if they are in the wrong order. You can read up on Bubble Sort and look at some sample cases here -
Once you understand the algorithm, the next step is implementing it in MATLAB.
arr = [5 4 3 2 1];
arr_size = length(arr);
for j = 0 : arr_size-1
for i = 1: arr_size-j-1
if arr(i)>arr(i+1)
temp = arr(i);
arr(i) = arr(i+1);
arr(i+1) = temp;
end
end
end
##### 1 CommentShowHide None
Jan on 7 Sep 2021
Although this is a sorting, it does not produce the wanted output:
B= [ 0 1 2 3 4 5 0 -6 -7 -8 0 9 10 11 0 -12 -13]

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