How to merge two column cell arrays into one, with alternating values?

A = ones(5,1);

B = zeros(5,1);

Assuming A and B will always be the same size, how can I get the result? I can't seem to find the right way of using reshape to achieve this.

C = {1 0 1 0 1 0 1 0 1 0}

Thanks in advance

[Awais Saeed]

I think you meant to merge two vectors. Cell arrays are different data types. Anyways, here is the reshape you want

% Specify [] for the first dimension to let reshape automatically 
% calculate the appropriate number of rows.
% 1 is the number of column
c = reshape([A B]',[],1)
c = c'

[Jerki Jokne]

Thanks! I did mean cell arrays, but I realize that the example I gave was numeric. Your answer works for cell arrays also.

A = {'a', 'b', 'c', 'd', 'e'};
B = {'1','2','3','4','5'};
C = reshape([A B]', [], 1)'

If you want to add your response as an answer, I will accept it. Thanks!

[Stephen23]

No need for the second transpose, just specify the desired output size when reshaping:

C = reshape([A,B].',1,[])

[Awais Saeed]

You are welcome @Jerki Jokne. It’s good that you got the result.

Answer 1

[tiwwexx]

I would create a matrix with size a+b then fill it in using steps of two.

a=zeros(1,5);
b=ones(1,5);
c= zeros(1,size(a,2)+size(b,2));
c(1:2:end)=a;
c(2:2:end)=b;