Size of hist3 output

Hi,

I would like to compute the a bivariate histogram by specifying the bin boundaries rather than centers. I've beed doing this with the hist3 function by specifying bin edges. I am wounding why the output of hist3 is size length(edges{1}) x length(edges{2}) rather than length(edges{1})-1 x length(edges{2})-1. Typically x number of specified bin boundaries give x-1 number of bins. Can anyone clarify this to me?

Answer 1

[Jan]

See e.g. the help text of histc:

 N(k) will count the value X(i) if EDGES(k) <= X(i) < EDGES(k+1).  The
 last bin will count any values of X that match EDGES(end).

Therefore you get k results for k-1 intervals.