help creating array from binary code

I have this sequence with your right numbering indicating the order.

0 (1) 0 (2) 0 (3) 1 (4) 1 (5) 0 (6) 0 (7) 0 (8) 0 (9) 0 (10) 1 (11) 0 (12) 0 (13) 0 (14) 0 (15)

  1 (16) 0 (17) 0 (18) 1 (19) 1 (20).

As would be the code to create the following matrix?

0 (18) 1 (19) 1 (20)

0 (15) 0 (17) 1 (19)

0 (12) 0 (15) 0 (18)

0 (9) 0 (13) 0 (17)

0 (6) 1 (11) 1 (16)

0 (3) 0 (9) 0 (15)

Answer 1

[Image Analyst]

out = zeros(6,3); % Initialize
% First column
out(:,1) = inputMatrix(18:-3:3,1);
% Second column
out(:,2) = inputMatrix(19:-2:9, 2);
% Third column
out(:,3) = inputMatrix(20:-1:15, 3);

It would be easy to generalize this for different sized input matrix, but you haven't said you need to do that (plus it's easy enough for you to figure out yourself).

[FRANCISCO]

sorry, I said the generalization. I could tell it would be like to use it with other sizes? thank you very much

[Image Analyst]

Like I said, it's really easy so I'm pretty sure you can do it. This may help:

L = length(inputMatrix);
out(:,1) = inputMatrix(L-2:-3:1,1);

See if you can get the rest. I can't really do it for you because you didn't say what's constant in the output matrix - the number of rows or the number of columns, or if both vary, how you decide on the number of rows and columns.

[FRANCISCO]

if true % code %s= sequence numbered 1 to 20 n=length(s);

d=3; %in this case is 3, but may be 4, 5, .....

end Now I do not know how to continue because the dimension of the matrix do not match what is calculated in matlab

How to make so that the dimension of the matrix automatically calculates it me?, Ie you enter your order will:

out = zeros (6,3);% Initialize

But this is as it should be to do it automatically?