Adding 2 vectors in a specified position

Hi, my question feel actually pretty easy but i am stuck.

Basically i want to obtain "z" with the even positions containing "y" and the odd position containing "x" (z=[1 12 2 13 3 14 ... 21 11])

How can i do this?

Thanks in advance

x=[ 1 2 3 4 5 6 7 8 9 10 11];
y=[12 13 14 15 16 17 18 19 20 21];

z=zeros(1,21);

for i=1:2:21
    for j=1:length(x)
        for k=1:length(y)
            z(i)=x(j);
        z(i+1)=y(k);
        end
    end
end

Answer 1

[Image Analyst]

Try this:

% Obtain "z" with the even positions containing "y" and 
% the odd position containing "x" (z=[1  12  2  13  3  14 ... 21  11])
x=[ 1 2 3 4 5 6 7 8 9 10 11];
y=[12 13 14 15 16 17 18 19 20 21];
z = zeros(1, length(x) + length(y));
% Counters for each independently allow for different lengths of x and y.
xCounter = 1;
yCounter = 1;
for k = 1 : length(z)
	if mod(k, 2) == 1 && xCounter <= length(x)
		z(k) = x(xCounter);
		xCounter = xCounter + 1;
	elseif yCounter <= length(y)
		z(k) = y(yCounter);
		yCounter = yCounter + 1;
	end
end
z % Report to command window.

[Image Analyst]

Note: if x and y are known to be the same length (which they are not in your example), it can be easier:

x=[ 1  2  3  4  5  6  7  8  9 10 11];
y=[12 13 14 15 16 17 18 19 20 21 22]; % Same length as x
z = reshape([x; y], 1, [])

[Dario Saracchi]

Thank you so much!