Hey all, I have a cell array of (5x3) (Vel{k,l}) and each contains 20000x4 matrix. I'd like to get mean value of cell arrays over the each column.At the end I should have 1x3 cell with 20000x4 matrix. I've searched the previous questions but couldn't figure it out. Thanks in advance.
%M_all{k,l}=mean(Vel{k,l},3);
cellfun(@mean,Vel{k,l});

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Image Analyst
Image Analyst am 17 Jul. 2021
Bearbeitet: Image Analyst am 17 Jul. 2021

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Then maybe just try a simple for loop. Untested code:
[rows, columns] = size(Vel);
averageArray = cell(1, columns);
for col = 1 : columns
sumArray = zeros(rows, columns);
for row = 1 : rows
thisArray = Vel{row, col};
sumArray = sumArray + thisArray;
end
averageArray{col} = sumArray / rows;
end

5 Kommentare

mehtap agirsoy
mehtap agirsoy am 18 Jul. 2021
Thanks for the help. sumArray creates 3x2 zero matrix but thisArray is 20000x4 so matrix dimensions do not agree. I got your idea but couldn't fix my code.Attached is my code if you're able to quide me I'd be glad. Thanks in advance
Image Analyst
Image Analyst am 18 Jul. 2021
Attach Vel in a .mat file also.
mehtap agirsoy
mehtap agirsoy am 18 Jul. 2021
Attached you can find it. I'm glad, thanks.
This works:
% Setup to get Vel.
s = load('Vel.mat')
Vel = s.Vel;
% Now we have Vel and we can start.
[rows, columns] = size(Vel)
[rows2, columns2] = size(Vel{1,1})
averageArray = cell(1, columns);
for col = 1 : columns
sumArray = zeros(rows2, columns2);
for row = 1 : rows
thisArray = Vel{row, col};
[rows2, columns2] = size(thisArray);
fprintf('The cell of Vel at row %d, column %d contains an array that is %d rows by %d columns.\n',...
row, col, rows2, columns2);
sumArray = sumArray + thisArray;
end
averageArray{col} = sumArray / rows;
end
mehtap agirsoy
mehtap agirsoy am 18 Jul. 2021
Million thanks,I was stucked and you really saved my life I really appreciate

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