can anyone explain how to do this
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A spring is stretched by 175 mm an 8 kg block. If the block is displaced 100 mm downward from its equilibrium position and given a downward velocity of 1.50 m/s, determine the differential equation which describes the motion. Assume that positive displacement is downward. Determine the position of the block when the weight decreased from 8 kg until 4 kg?
Jonas on 11 Jul 2021
so if you put 8kg on the spring it moves 175mm down and does not move further. this means there is a force equlibrium between the weight and the spring which you can use to calculate the spring constant k
from that you can also solve the 4kg question
the motion will follow a cosine function A*cos(2*pi*f*t). the frequency is sqrt(k/m)/(2*pi), the amplitude is given and the starting speed gives you the condition for the dervative of the motion