Could anyone help me to get the result for the following code.

I am having a cell array B=6x1 cell as

1x1 cell -[1]

1x1 cell-[1]

1x1 cell-[1,2]

1x2 cell-[1] [2]

1x2 cell-[1] [2,3]

1x2 cell-[1,2] [3]

Here, the entire cell array contain 12 values. Based on 12 values I having a matrix A as below:

A=[0.3882 -1

0.9808 - 1

0.6832 -1

0.1033 -2

0.3565 -1

0.4774 -2

0.0767 -1

0.1286 -2

0.3660 -3

0.6500 -1

0.4370 -2

0.6444 -3

In A, the bold number (0.6832 0.1033), (0.1286,0.3660),(0.6500,0.6444) needs to be considered together as they corresponds to [1,2], [2,3], [1,2]

using this B and A i need to compute C which perms log operation.

I tried using for loop for it, but for first cell array it considers all the 12 values in A instead of considering only the first value.

Here is the code

B=6x1 cell array
A[ 0.3882
    0.9808
    0.6832
    0.1033
    0.3565
    0.4774
    0.0767
    0.1286
    0.3660
    0.6500
    0.4370
    0.6444]
for d=1:length(B)
for e=1:length(B{d})
for u =1:size(A,1)
C
end
end  
end

Could anyone please help me how i can compute C by considering the required values in A with respect to B.

[Walter Roberson]

If you do not want all 12 to be considered, then your for u loop should not loop to the number of rows in A.