How to define both integer and decimal increment in one for loop?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Susan
am 23 Jun. 2021
Bearbeitet: Susan
am 24 Jun. 2021
Hi all,
I would like to define one for loop that goes from 0 to 1 with an increment of 0.1 and then goes from 1 to 30 by an increment of 2, i.e., combination of the following two loops. Is it possible? If so, how?
for n = 1:2:30
f(round((n-1)/2+1)) = ....
end
z = 0: 0.1: 1;
for n = 1: length(z)
f(n) = ..
end
Thanks in advance
0 Kommentare
Akzeptierte Antwort
Image Analyst
am 23 Jun. 2021
Try this:
allValues = [0:0.1:1, 3:2:30];
numValues = length(allValues)
% Preallocate some results we want to store in the loop.
results = zeros(1, numValues);
% Now loop over all values.
for k = 1 : numValues
thisValue = allValues(k);
fprintf('Processing element #%d of %d, which is %f.\n', ...
k, numValues, thisValue);
% results(k) = YourFunction(thisValue);
end
Weitere Antworten (1)
millercommamatt
am 23 Jun. 2021
I'm not clear on what you're looking for. Do you want something like this:
span1 = 0:0.1:1;
span2 = 3:2:30;
span = [span1 span2];
for ii = span
% do something with ii...
end
7 Kommentare
Steven Lord
am 24 Jun. 2021
@Matthew I suspect Image Analyst was replying to Susan's message not yours. The comment "do something with ii..." suggests to me (and I suspect to Image Analyst as well) that Susan wanted output(ii).
Image Analyst
am 24 Jun. 2021
I was responding to Susan and just said No, then I went to MATLAB to develop code that works. Then I came back here to further explain why it wouldn't work and edited my comment but then I didn't notice miller's comment since it was posted while I was working on the code in MATLAB, and I mistakenly copied the loop from miller's comment instead of Susan's (not noticing that millers was a new comment). Sorry for the misunderstanding, that sometimes happens when people are posting at the same time. miller's code snippet #2 will also work for Susan.
Siehe auch
Kategorien
Mehr zu Feature Detection and Extraction finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!