Could anyone help me how to simplify the following code.
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jaah navi
am 23 Jun. 2021
Kommentiert: jaah navi
am 23 Jun. 2021
A = cell(1,15)
B=A'
B{1}=cell(2,1)
B{2}=cell(2,1)
B{3}=cell(2,1)
B{4}=cell(2,1)
B{5}=cell(2,1)
B{6} = cell(2,2)
B{7}= cell(2,2)
B{8} = cell(2,2)
B{9}= cell(2,2)
B{10} = cell(2,2)
B{11}= cell(2,3)
B{12}= cell(2,3)
B{13}= cell(2,3)
B{14}= cell(2,3)
B{15}= cell(2,3)
in this code instead to write each and every row of the cell array separately is there any method that could be done to simplify it in the single step. For example B{1}.......B{5} are of the same size(2,1) ,B{6}.......B{10} of (2,2) , B{11}.....B{15} of (2,3) .IS it possible to write all the lines in a single step.
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KSSV
am 23 Jun. 2021
Why you are bothered to initialize a cell in each cell in an cell array? You are missing something here.
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Mohammad Sami
am 23 Jun. 2021
I am not sure why you are creating a nested cell array. However you can do it like this.
B = arrayfun(@(x,y)cell(x,y),ones(15,1)*2,repelem([1:3]',5,1),'UniformOutput',false)
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