Hi...
I need to finde the RPM from a vector of radians and a vector of seconds (time).
I can do this manually by doing this:
rpmArray = (radiansArray/(2*pi));
minutesArray = timeArray/60;
slopeArray = [];
for counter = 1:length(minutesArray)
if counter < length(minutesArray)
x1 = minutesArray(counter);
x2 = minutesArray(counter + 1);
y1 = rpmArray(counter);
y2 = rpmArray(counter + 1);
slopeArray(counter) = (y2-y1)/(x2-x1);
end
end
slopeArray(end + 1) = slopeArray(end); % Fill in the missing entry
I can not figure out how to do this the "smart way" by using Matlabs diff().
Can anyone help me?

3 Kommentare

Walter Roberson
Walter Roberson am 21 Jun. 2021
Perhaps use gradient() ?
Kenneth Metzsch
Kenneth Metzsch am 21 Jun. 2021
I think it gives me the same problem as diff().
It assumes spacing is 1.
Can you give me an example of how to overcome this?
Stephen23
Stephen23 am 21 Jun. 2021
"It assumes spacing is 1."
Did you look at the h/hx/hy inputs?

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Chunru
Chunru am 21 Jun. 2021

0 Stimmen

rpmArray = (radiansArray/(2*pi));
minutesArray = timeArray/60;
slopeArray = gradient(rpmArray)./gradient(minuteArray);

1 Kommentar

Thank you...it works
Actually it wil also work with diff() like this
rpmArray = (radiansArray/(2*pi));
minutesArray = timeArray/60;
slopeArray = diff(rpmArray)./diff(minutesArray);
slopeArray(end + 1) = slopeArray(end);

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