Generating a normal distrbution random numbers and setting them to catagories

1 Ansicht (letzte 30 Tage)
Hello,
Im very much new to matlab and would love help on this script.
I have to generate (n) amount of numbers, then set a,b and c to their catagories a is <-0.25 , b is >-0.25 and <=0.25 , c is >0.25
as well as find the sum of each catagories
function [a,b,c,Asum,Bsum,Csum]=random_gen(n)
a=0;
b=0;
c=0;
Asum=0;
Bsum=0;
Csum=0;
r=randn(1,n)
for n=1:n
if r(n)<-0.25
a=a+1
Asum=Asum+r(n)
elseif r(n)>=-0.25 && r(n)<=0.25
b=b+1
Bsum=Bsum+r(n)
elseif r(n)>0.25
c=c+1
Csum=sum+r(n)
end
end
  3 Kommentare
Thang Lian
Thang Lian am 17 Jun. 2021
Ive updated the question. Sorry for the confusion. The code runs but I was wondering if there are any syntax that could make it simplier.
dpb
dpb am 17 Jun. 2021
"any syntax that could make it simplier."
See the Answer supplied below...

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Antworten (2)

dpb
dpb am 17 Jun. 2021
function [abc,ABC]=random_gen(n)
r=randn(n,1); % generate column vector N rn
ix=discretize(r,[-inf -0.25 0.25 inf]); % bin into three bins
abc=arrayfun(@(i)x(ix==i),1:3,'UniformOutput',0); % return binned values (3-cell array)
ABC=accumarray(ix,r); % return bin sums (3-array)
end

Walter Roberson
Walter Roberson am 17 Jun. 2021
Asum = Asum+a(n)
You have
a(n)=r(n);
Suppose it is true for n = 2 and 5. Then assigning to a(2) would create a(1) as 0, and assigning to a(5) would create a 3 and a 4 as 0. And if the total run was 10 then a6 onwards would not exist.

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Version

R2021a

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