Why does my V returns a single scalar value?

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Amanda Liu
Amanda Liu am 16 Jun. 2021
Kommentiert: Amanda Liu am 17 Jun. 2021
% Given
P = 3000;
E = 7e10;
h = 0.1;
b = 0.005;
t = 0.008;
w1 = 0.15;
w2 = 0.09;
L = 2;
% Input
x0=0;
dt=0.1;
x=x0:dt:L;
W=@(x) (x>=0 & x<=L/2).*w1 + (x>L/2).*w2;
w=W(x);
I=(w*h^3-(h-2*t)^3*(w-b))/12;
V=(P*x.^2).*(3*L-x)/(E*I);

Akzeptierte Antwort

Stephen23
Stephen23 am 16 Jun. 2021
Bearbeitet: Stephen23 am 16 Jun. 2021
You are using the wrong divide operator:
V=(P*x.^2).*(3*L-x)./(E*I)
% ^^

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