how to form a two-column array for a given but dimmension-unknown array?

Dear All,
I have two array with the same length A and B. I want to form another array C which is formed by A and B. But the dimmensions of A and B are uncertain, sometimes A (B) is a row vector so that C = [A' B'], but sometimes A (B) is a column vector so that C = [A B].
I am wondering if there is a simple way to form array C without checking the dimmensions of A and B.
Thanks.
Benson

 Akzeptierte Antwort

Stephen23
Stephen23 am 10 Jun. 2021
Bearbeitet: Stephen23 am 10 Jun. 2021
"I am wondering if there is a simple way to form array C without checking the dimmensions of A and B."
C = [A(:),B(:)]

Weitere Antworten (1)

Joel Lynch
Joel Lynch am 9 Jun. 2021
Bearbeitet: Joel Lynch am 10 Jun. 2021
You can make a row vector of any N dimensional matrix by linearizing, for example
A( 1:numel(A), 1 ) = A(:);
.Thus, you can always make
C = C(1:numel(A),1:2) = [ A(:) , B(:) ];

4 Kommentare

Hi, Joel,
I run your code. But the second C = C(1:numel(A),2) = [ A(:) , B(:) ] has the following error message:
Index exceeds array bounds.
Error in function_sub (line 506)
C = C(1:numel(A),2) == [ A(:) , B(:) ];
Thanks a lot.
Benson
Sorry, should be C(1:numel(A),1:2)=…
or more simply, C=…
I just included the indices so it was clear what size C would be.
I got the following error message again.
Error using horzcat
Dimensions of arrays being concatenated are not consistent.
Thanks.
Benson
Assuming A and B have the same number of elements, then C=[A(:),B(:)]; should work.
Make sure A, B, and C are cleared and reset before trying this. numel(A) and numel(B) should be the same. And C should not be defined.

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