summing up array element

Hello,
I am new to programming, I have an array like p = [3 6 2 5];
I need c = [3 9 11 16]; First element in the array is as it is, when it goes to next element it has to sum the previous element.
Regards, SBN

Antworten (4)

Cedric
Cedric am 25 Jul. 2013
Bearbeitet: Cedric am 25 Jul. 2013

2 Stimmen

Hi, use CUMSUM:
>> p_csum = cumsum(p)
p_csum =
3 9 11 16

2 Kommentare

Bathrinath
Bathrinath am 25 Jul. 2013
Thanks it works. Can you give the solution in for loop .
Cedric
Cedric am 25 Jul. 2013
Bearbeitet: Cedric am 25 Jul. 2013
Did you try building a solution based on a FOR loop? What did you implement so far?

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Evan
Evan am 25 Jul. 2013
Bearbeitet: Evan am 25 Jul. 2013

1 Stimme

help cumsum
>> s = cumsum(p)
s =
3 9 11 16

1 Kommentar

Bathrinath
Bathrinath am 25 Jul. 2013
Thanks it works. Can you give the solution in for loop .

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Andrew Reibold
Andrew Reibold am 25 Jul. 2013
Bearbeitet: Andrew Reibold am 25 Jul. 2013

1 Stimme

Here is your solution in a really easy loop.
p = [3 6 2 5]; %Can have as many numbers as you want
for n = 2:length(p) %n can be whatever counter you want.
p(n) = p(n)+p(n-1); %semi-colon suppresses output
end
-Andrew
Iain
Iain am 25 Jul. 2013
Bearbeitet: Iain am 25 Jul. 2013

0 Stimmen

for i = 1:numel(p)
c(i) = sum(p(1:i));
end
Or
so_far = 0;
for i = 1:numel(p)
so_far = so_far + p(i);
c(i) = so_far;
end
or
for i = 1:numel(p)
s = 0;
for j = 1:i
s = s+ p(j);
end
c(i) = s;
end

1 Kommentar

Jan
Jan am 25 Jul. 2013
These are inefficient solutions, because the complete sum is calculated in each iteration. While this might not matter for 4 elements, the runtime will grow rapidly for longer data.
It is more efficient to re-use the sum for the elements 1 to i, when the sum until the i+1.th element is obtained. See Andrews answer.

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am 25 Jul. 2013

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am 11 Sep. 2021

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