Filter löschen
Filter löschen

a problem with a function

4 Ansichten (letzte 30 Tage)
Rica
Rica am 23 Jul. 2013
hi all ! i wrote this simple function
%
function [ output_args ] = fract_int16( input_args )
if input_args<0
output_args=round(2^16+input_args*2^15);
else
output_args=round(input_args*2^15);
end
end
when i use it for negative number for exemple
%
fract_int16(-0.9133)=35609
fract_int16(0.3481)=11409,
both values ARE TRUE
but when use this function in an array i get a false value
%
A=[-0.9133 0.3481]
fract_int16(A)=[-29927 11407]
this is wrong!!
did i make i mistake in writing this function?
thank you all

Akzeptierte Antwort

David Sanchez
David Sanchez am 23 Jul. 2013
Try this out:
input_args = [-0.9133 0.3481];
output_args = zeros(size(input_args));
for k=1:length(input_args)
if input_args(k)<0
output_args(k)=round(2^16+input_args(k)*2^15);
else
output_args(k)=round(input_args(k)*2^15);
end
end

Weitere Antworten (2)

Narges M
Narges M am 23 Jul. 2013
Bearbeitet: Narges M am 23 Jul. 2013
Yes, your function is designed to work with one value, and see if that's less than zero or not. So if you want to use it for arrays you need to use a loop either in the function or when calling it. Right now, if any of the array values are less than zero, if would fire TRUE, and then the output would be calculated for the whole array.

Jan
Jan am 23 Jul. 2013
And a faster vectorized version:
function output_args = fract_int16(input_args)
output_args= 2^16 * (input_args < 0) + round(input_args * 2^15);
end

Kategorien

Mehr zu Data Type Conversion finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by