I created an array of objects in app designer. They're all images.
images=[app.Image1,app.Image2,.......,app.ImageX];
now I get their visible property
check=get(images,'Visible');
that gives me a cell array of 'on' and 'off' values. I want to check if all the values in the array are 'on'. How do I do that? I tried combining it into a matrix, but got errors.

 Akzeptierte Antwort

DGM
DGM am 26 Apr. 2021
Bearbeitet: DGM am 26 Apr. 2021

0 Stimmen

Consider the example
A = {'on'};
A = repmat(A,[10 1])
% A{2} = 'off' % uncomment to test the response to the existence of an 'off' instance
f = @(x) strcmp(x,'on');
allon = all(cellfun(f,A)) % returns scalar logical
EDIT:
Actually, Image Analyst has a point. The regular string comparison tools would be simpler (about 50x faster too) and don't even need cellfun()
allon = all(strcmp(A,'on'))
I don't know why I chose to use cellfun() for that. I just had it on my mind at the time and ran with it.

Weitere Antworten (2)

Image Analyst
Image Analyst am 26 Apr. 2021

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Try this:
>> ca = {'on', 'on', 'on'}
ca =
1×3 cell array
{'on'} {'on'} {'on'}
>> allOn = all(ismember(ca, {'on'}))
allOn =
logical
1
>> ca = {'on', 'on', 'off'}
ca =
1×3 cell array
{'on'} {'on'} {'off'}
>> allOn = all(ismember(ca, {'on'}))
allOn =
logical
0

3 Kommentare

Vojtech Siler
Vojtech Siler am 26 Apr. 2021
This is giving me this error:
Error using cell/ismember (line 34)
Input A of class cell and input B of class cell must be cell arrays of character vectors, unless one is a character vector.
Image Analyst
Image Analyst am 27 Apr. 2021
You changed something. My code works. I don't have 34 lines in my code. I had only 2 lines and they worked. You don't need anonymous functions, strcmp(), cellfun(), etc. All you need is the single line of code I gave you that calls ismember().
Vojtech Siler
Vojtech Siler am 27 Apr. 2021
I inserted this code into my code and changed the name of the array to what I had.

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Steven Lord
Steven Lord am 26 Apr. 2021
One easy way to do this is to use a string.
A = {'on', 'on', 'on'};
all(A == "on")
ans = logical
1

2 Kommentare

Vojtech Siler
Vojtech Siler am 26 Apr. 2021
I think I remember trying that, because I found a similar thing as an answer to a similar problem, but I think it threw errors. I'll try this specifically tomorrow, though, and see if it works. Thanks for the answer!
DGM
DGM am 27 Apr. 2021
It depends what version you have. This usage with the double quoted string needs R2016b to work (IIRC). At least it doesn't work for me in R2015b.

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