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The variable in parfor cant classified

2 Ansichten (letzte 30 Tage)
freebil
freebil am 4 Jul. 2013
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
Hello.This is my code:
c_hat = zeros(n,1);
vc = zeros(m,n);
cv = zeros(m,n);
parfor j = 1:n
checks = find(H(:,j));
allIncoming = cv(checks,j);
sumAllIncoming = sum(allIncoming) + LLRs(j);
c_hat(j) = (1 - sign(sumAllIncoming))/2;
toCheck = sumAllIncoming - allIncoming;
vc(checks,j) = toCheck;
end
It is not runing because "The variable vc in a parfor cannot be classified." Without parfor it is running fine. Is it possible to run it with parfor?

Antworten (1)

Matt J
Matt J am 4 Jul. 2013
Bearbeitet: Matt J am 4 Jul. 2013
There are rules about sliced variables and how you can index them in parfor loops. However, you can get around these rules by re-organizing vc and cv as cell arrays,
c_hat = zeros(n,1);
vc = num2cell(zeros(m,n),1);
cv = vc;
parfor j = 1:n
checks = H(:,j)~=0;
allIncoming = cv{j}(checks);
sumAllIncoming = sum(allIncoming) + LLRs(j);
c_hat(j) = (1 - sign(sumAllIncoming))/2;
toCheck = sumAllIncoming - allIncoming;
vc{j}(checks) = toCheck;
end
vc=[vc{:}]; %convert back to normal array
  7 Kommentare
freebil
freebil am 4 Jul. 2013
Really thanks for the answers. @Jan Simon line 35 was
vc{j}(checks) = toCheck;
and line 19 was
parfor j = 1:n
@Matt J I changed them but now i have the error
Index exceeds matrix dimensions.
Error in decodeBP (line 52)
allIncoming = tanh(vc{j}(vars)/2);
Matt J
Matt J am 4 Jul. 2013
Bearbeitet: Matt J am 4 Jul. 2013
I take it back. Put this back
vc=[vc{:}];
but add immediately after it
vc=num2cell(vc,2);
Also, please learn to use DBSTOP to trap and investigate common errors like "Index exceeds matrix dimensions." and "Conversion to cell from double is not possible."

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