FOR LOOP , beginner question.

i want to Write a code or script including a FOR LOOP in order to computing the value of d for the following values of x and returning an output variable named ANSWER just as shown : x = 0.10, x = 0.15, and x = 0.20

[Daniel Pollard]

Can you give more detail, such us -

1. Where do these numbers come from? How were they found in the first place?
2. What have you tried so far?
3. What sort of calculation do you expect to be inside the for loop?

[Hamada Alkhlif]

sorry i forgot to entionb the eqation that we should use for d

1. d=((34.63/x)-5.162)/2.54

1. d = [];
2. for x=[0.1000,0.1500,0.2000]
3. d=[d ((34.63/x)-5.126)/2.54];
4. disp ("ANSWER");
5. end
6. x=[0.1000 0.1500 0.2000];
7. fprintf("\t%4g\t\t%4g\n",[x;d])

but when i put this cod into matlab it display like this

for x it shoulkd be 4 decimals .

[DGM]

Try

fprintf("\t%8.4f\t%8.4f\n",[x;d])

using %g strips insignificant trailing zeros

Answer 1

[Daniel Pollard]

Your code is

d = [];
for x=[0.1000,0.1500,0.2000]
    d=[d ((34.63/x)-5.126)/2.54];
    disp ("ANSWER");
end
x=[0.1000 0.1500 0.2000];
fprintf("\t%4g\t\t%4g\n",[x;d])

If I understand right, you want

d = [];
x=[0.1000,0.1500,0.2000];
for xi = 1:numel(x)
    d=[d ((34.63/x(xi))-5.126)/2.54];
    disp ("ANSWER");
    fprintf("\t%5.4f\t\t%.4f\n", [x(xi);d(xi)])
end

[Hamada Alkhlif]

answer for your first code

>> Untitled6

ANSWER

ANSWER

ANSWER

0.1 134.32

0.15 88.8743

0.2 66.1512

>>

answer for second code you gave :

>> Untitled3

ANSWER

0.1000 134.3205

ANSWER

0.1500 88.8743

ANSWER

0.2000 66.1512

>> this one coorect accept the fact that there are 3 answer words. it must be 1 answer word and 3 rows and 2 coloms with 4 decimals for x' and d'

[Daniel Pollard]

My apologies - try

d = [];
x=[0.1000,0.1500,0.2000];
disp ("ANSWER");
for xi = 1:numel(x)
    d=[d ((34.63/x(xi))-5.126)/2.54];
    fprintf("\t%5.4f\t\t%.4f\n", [x(xi);d(xi)])
end

[Hamada Alkhlif]

almost the correct answer after i use the code in matlab i got this answer :

ANSWER

0.1000 134.3205

0.1500 88.8743

0.2000 66.1512

which is almost the same as the output asked above but one thing does not seems right here ,the last 3 numbers of (d') are not alighned , in other word (5 ,3 .2 ) should be alighned vertically .

thank you @Daniel Pollard

[DGM]

Use a wider field width as in the example I gave

fprintf("\t%8.4f\t%8.4f\n",[x;d])

It could be tightened up as necessary.

[Hamada Alkhlif]

i did and finally i got the wanted answer .

thank you @DGM

[Hamada Alkhlif]

thank you @Daniel Pollard

[Hamada Alkhlif]

thanks everybody

Answer 2

[Jan]

disp ("ANSWER");
for x = [0.10, 0.15, 0.20]
   d = ((34.63 / x) - 5.126) / 2.54;
   fprintf("%12g%12g\n", x, d)
end

Or:

x = [0.10, 0.15, 0.20]
d = ((34.63 ./ x) - 5.126) / 2.54;  % .7 for elementwise division

fprintf('Answer:\n');
fprintf("%12g%12g\n", [x, d].')

[Hamada Alkhlif]

1st code gives :

>> Untitled3

ANSWER

0.1 134.32

0.15 88.8743

0.2 66.1512

>> the answer here does not have 4 decimals for x' and not alighed vertically , same for d'

2nd code gives :

>> Untitled3

x =

0.1000 0.1500 0.2000

Answer:

0.1 0.15

0.2 134.32

88.8743 66.1512

>>