Matlab don't show calculated variables.

1 Ansicht (letzte 30 Tage)
Tiago Araujo
Tiago Araujo am 13 Apr. 2021
Bearbeitet: Walter Roberson am 14 Apr. 2021
I wrote this:
syms C0 C1 C2 C3 X L P EI1 EI2
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
dY(X)=diff(Y(X),X);
d2Y(X)=diff(dY(X),X);
f0 = Y(0) == 0;
f1 = Y(L) == 0;
R=solve([f0,f1],[C0,C1]);
C0 = R.C0;
C1 = R.C1;
U=(EI1/2)*int(d2Y(X)^2,[0 L/2])+(EI2/2)*int(d2Y(X)^2,[L/2 L]);
V=-P*Y(L/2);
PI(C2,C3)=U+V;
dPIdC2=diff(PI(C2,C3),C2);
dPIdC3=diff(PI(C2,C3),C3);
f2 = dPIdC2 == 0;
f3 = dPIdC3 == 0;
S=solve([f2,f3],[C2,C3]);
C2 = S.C2;
C3 = S.C3;
C= ([C0;C1;C2;C3]);
disp(C);
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
disp Y(X);
disp (Y(X));
FLECHA = Y(L/2)
But Matlab returns:
C =
0
- C3*L^2 - C2*L
(P*(EI1*L + 11*EI2*L))/(4*(EI1^2 + 14*EI1*EI2 + EI2^2))
-(P*(EI1 + 7*EI2))/(6*(EI1^2 + 14*EI1*EI2 + EI2^2))
______________________________________________
Y(X)
C3*X^3 + C2*X^2 + C1*X + C0
FLECHA
(C3*L^3)/8 + (C2*L^2)/4 + (C1*L)/2 + C0
It dont show Y(X) in terms of calculated values of C0, C1, C2 and C3.
I Want the Y(x) in function of P, L, EI1, EI2, (...), with this script these variables C0, C1... are calculateds but MATLAB dont write Y(X) em terms of them.

Akzeptierte Antwort

Tiago Araujo
Tiago Araujo am 14 Apr. 2021
Bearbeitet: Walter Roberson am 14 Apr. 2021
I fixed doing:
syms C0 C1 C2 C3 X L P EI1 EI2
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
dY(X)=diff(Y(X),X);
d2Y(X)=diff(dY(X),X);
f0 = Y(0) == 0;
f1 = Y(L) == 0;
U=(EI1/2)*int(d2Y(X)^2,[0 L/2])+(EI2/2)*int(d2Y(X)^2,[L/2 L]);
V=-P*Y(L/2);
PI(C2,C3)=U+V;
dPIdC2=diff(PI(C2,C3),C2);
dPIdC3=diff(PI(C2,C3),C3);
f2 = dPIdC2 == 0;
f3 = dPIdC3 == 0;
S=solve([f0,f1,f2,f3],[C0,C1,C2,C3]);
C0=S.C0;
C1=S.C1;
C2 = S.C2;
C3 = S.C3;
C= ([C0;C1;C2;C3]);
disp(C);
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
disp Y(X);
disp (Y(X));
FLECHA = Y(L/2)

Weitere Antworten (1)

Jan
Jan am 14 Apr. 2021
I get a dfifferent output than you:
syms C0 C1 C2 C3 X L P EI1 EI2
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
dY(X)=diff(Y(X),X);
d2Y(X)=diff(dY(X),X);
f0 = Y(0) == 0;
f1 = Y(L) == 0;
R=solve([f0,f1],[C0,C1]);
C0 = R.C0;
C1 = R.C1;
U=(EI1/2)*int(d2Y(X)^2,[0 L/2])+(EI2/2)*int(d2Y(X)^2,[L/2 L]);
V=-P*Y(L/2);
PI(C2,C3)=U+V;
dPIdC2=diff(PI(C2,C3),C2);
dPIdC3=diff(PI(C2,C3),C3);
f2 = dPIdC2 == 0;
f3 = dPIdC3 == 0;
S=solve([f2,f3],[C2,C3]);
C2 = S.C2;
C3 = S.C3;
C= ([C0;C1;C2;C3]);
disp(C);
Y(X)=C0+C1*X+C2*X^2+C3*X^3;
disp Y(X);
Y(X)
disp (Y(X));
FLECHA = Y(L/2)
FLECHA = 
  1 Kommentar
Tiago Araujo
Tiago Araujo am 14 Apr. 2021
Hi! Thanks!
But, have you seen that the C3 and C2 are still present in the Y(X) instead of their value in function of EI, P and L... ?
I need Y(X) only in function of EI1 EI2 P and L...

Melden Sie sich an, um zu kommentieren.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by