Matrix construction over a loop

1 Ansicht (letzte 30 Tage)
ASHA RANI
ASHA RANI am 11 Apr. 2021
Kommentiert: ASHA RANI am 12 Apr. 2021
x=[1:1:10];
a=2;
b=4;
c=6;
for i=1:length(x)
A=a*b/x(i);
B=c+A(i)/b;
D=a+b;
E=1-2*c;
MAT=[B(i);D;E];
M=sqrt([MAT])
end
I am not able to matrix corresponding to 10 values of x.
plz help
thanks
  1 Kommentar
David Fletcher
David Fletcher am 11 Apr. 2021
This line will create a scaler value for A
A=a*b/x(i);
On the following line you are trying to index a scaler value
B=c+A(i)/b;

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

VBBV
VBBV am 11 Apr. 2021
clear
x=[1:1:10];
a=2;
b=4;
c=6;
for i=1:length(x)
A(i)=a*b/x(i);
B(i)=c+A(i)/b;
D=a+b;
E=1-2*c;
MAT(i,:)=[B(i);D;E];
end
M=sqrt(abs(MAT))
  2 Kommentare
VBBV
VBBV am 11 Apr. 2021
In my solution, the Matrix MAT is not 3 x 1. It is 10 x 3 for which sqrt is possible and same as what you would get if you perform MAT.^(1/2) element wise operation.
ASHA RANI
ASHA RANI am 12 Apr. 2021
VBBV, thanks
Its works .

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Jan
Jan am 11 Apr. 2021
Maybe you want:
for i = 1:length(x)
A(i) = a * b / x(i);
B(i) = c + A(i) / b;
D(i) = a + b;
E(i) = 1 - 2 * c;
...

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by