how to understand .sc .mat in matlab
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello,i cant see the logic of these two lines taken from the full code shown bellow.
i know that its some how plotting an area but .mat .sc are resembling . command from c# of object oriented.
How to understand the meaning of the two lines shown bellow?
Is there any material i could use explaining examples for this structs?
Thanks
func_in.mat=NmidCirc;
func_in.sc=scale;
full code:
lambda=633e-9;% wave length in [m]
L=0.01;% meter factor, it is defined that 1cm=1024 pixels-> the first scale will be over 1cm
scale=linspace(-L/2,L/2,n);% basic scaling vector in length of 1024.
%% Q2 creating matrix
[X, Y]= meshgrid(scale,scale);% creating the basic function. on the function we will create the images that will operated
midCirc= X.^2+Y.^2<(1/n)^2;%because we work in meter units, the 100/1024[cm] transforms into 1/1024[m]
NmidCirc=not(midCirc);
Ring= ((X-0.8/n).^2+(Y-0.8/n).^2<(1/n)^2)&((X-0.8/n).^2+(Y-0.8/n).^2>(0.6/n)^2);
NRing=not(Ring);
Tshape= (abs(Y)<0.2/n)&(abs(X)<0.6/n) | ((Y<1.4/n)&(Y>0.2/n)&(abs(X)<0.2/n))
%%%% Negative cirle part
func_in.mat=NmidCirc;
func_in.sc=scale;
figure(2)
colormap gray
for j=1:6
func_out=Rdiv(func_in,lambda,Z(j),n);
subplot(2,3,j);
image(func_out.sc, func_out.sc, abs(func_out.mat), 'CDataMapping','scaled');
xlabel('[m]');
ylabel('[m]');
title(['Z=',num2str(Z(j))]);
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Get Started with Image Processing Toolbox finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!