Calling a function without an Output argument

11 Ansichten (letzte 30 Tage)
Telema Harry
Telema Harry am 5 Apr. 2021
Kommentiert: Adam Danz am 6 Apr. 2021
Hi Programmers,
I have a function that plots the phase and magnitude of my signal.
I want this function to plot only the magnitude if no ouput argument is provided when the function is called.
Y = Myplot (a,b)
Y = figure(1)
subplot(2,1,1)
stem (a)
subplot(2,1,2)
stem (b)
% I want to plot only stem (a) when the function is called without the
% output argument.
Myplot (a,b)
stem (a)

Akzeptierte Antwort

Adam Danz
Adam Danz am 5 Apr. 2021
Bearbeitet: Adam Danz am 5 Apr. 2021
Use nargout to determine the number of output arguments.
if nargout==0
% do something
elseif nargout < 2
% do something else
end
  4 Kommentare
Telema Harry
Telema Harry am 5 Apr. 2021
I modified the code slightly and it gave me the intended result.
if nargout==0
% do something
elseif nargout > 0
% do something else
end
Thank you for your help.
Adam Danz
Adam Danz am 6 Apr. 2021
This can be simplified to
if nargout == 0
else
end

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

David Hill
David Hill am 5 Apr. 2021
Change the number of input arguments instead
function y=Myplot(varagin)
y=figure;
if nargin==2
subplot(2,1,1);
stem(varagin{1});
subplot(2,1,2);
stem(varagin{2});
else
stem(varagin{1});
end

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Produkte


Version

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by