all possible *UNIQUE* permutations of a binary vector
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eyal lampel
am 11 Jun. 2013
Kommentiert: winkmal
am 25 Sep. 2020
hello all, i am trying to make a griddler/nonogram puzzel solver with matlab.
to do so i need to find all possible UNIQUE permutations of a binary vector. for example :
input Vector: [1 0 1 0]
output matrix:
[1 0 1 0
1 0 0 1
0 1 0 1
0 0 1 1
0 1 1 0
1 1 0 0]
untile now i've been using the following code:
if true
inVec=[1 0 1 0]
outMat=perms(inVec);
outMat=unique(outMat,'rows')
end
This was perfectly fine but for inVec longer then 10 i get an: 'out of memory' error.
is it possible to do this without using perms/unique ? i need this for up to inVec length 20.
Thanks Lampel.
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Andrei Bobrov
am 11 Jun. 2013
Bearbeitet: Andrei Bobrov
am 12 Jun. 2013
c = [0 1];
cc = c(fullfact([2 2 2 2]));
out = cc(sum(cc,2) == 2,:);
A = [1 1 0 0];
n = numel(A);
k = sum(A);
c = nchoosek(1:n,k);
m = size(c,1);
out = zeros(m,n);
out(sub2ind([m,n],(1:m)'*[1 1],c)) = 1;
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Jan
am 11 Jun. 2013
Bearbeitet: Jan
am 11 Jun. 2013
Using UINT8 instead of DOUBLE will reduce the memroy footprint by a factor of 8.
[EDITED] Bad statistics removed. For 20 elements with 10 enabled bits you get 20!/(10! * (20-10)!) possible solutions, which mean 184'756 * 20 bytes if you use UINT8 values.
nElem = 20;
nEnabled = 10;
Index = VChooseK(uint8(1):uint8(nElem), nEnabled);
Result = [under construction], see Andrei's solution
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