Filter löschen
Filter löschen

how can I write code to reach my goal as figure below?

1 Ansicht (letzte 30 Tage)
kimy
kimy am 28 Mär. 2021
Kommentiert: kimy am 4 Apr. 2021
Hi guys,
P is a matrix with dimension i*j; n is an integer. How can I write this formula in matlab? Thanks.
  2 Kommentare
Adam Danz
Adam Danz am 28 Mär. 2021
What part are you having trouble with? How can we help without doing it for you?
kimy
kimy am 29 Mär. 2021
Hello Adam, in fact I was trying a loop to give the value for rij, also Ci and Vi However, the code I wrote must be wrong. Could you please give me some suggestions? Thanks.
for i=1:n
for j=1:n
for k=1:n
syms k
R(i,j)=symprod(P(i,k)*P(k,j),k,1,n)^(1/n)
C(i)=(symprod(R(i,k),k,1,n))^(1/n)
V(i)=C(i)/sum(C(k),k,1,n);
end
end
end

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Adam Danz
Adam Danz am 29 Mär. 2021
Bearbeitet: Adam Danz am 29 Mär. 2021
> in fact I was trying a loop to give the value for ri
r is an existing matrix. i and k are just indices. So the value of ri is just r(i,:) and the value of rik is r(i,k).
> also Ci and Vi
What's Vi?
For C, is this what you're looking for?
%n = ?? % scalar
%r = ?? % size nxn
C = nan(1,n);
for i = 1:n
C(i) = nthroot(prod(r(i,1:n)),n);
end
which is the same as
%n = ?? % scalar
%r = ?? % size nxn
C = nthroot(prod(r(1:n,1:n),2),n)
  3 Kommentare
Adam Danz
Adam Danz am 29 Mär. 2021
I don't follow what you're saying and it seems like the question and background information is changing with each comment. I've already reached my allotted volunteer time for the day but I can check back later to see if there is a crystal clear question with all the needed background information.
kimy
kimy am 4 Apr. 2021
Sorry, now I solved the problem. But the following comlicated formula seems not so easy to write, could you please give me some suggestions? Thanks.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by