Inserting new element after each element of an array
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Neeraj Chimwal
am 25 Mär. 2021
Bearbeitet: DGM
am 26 Mär. 2021
I have an array arr = [2,4,6]
After converting this array elements to binary using de2bi(arr,'left-msb'), I get
0 1 0
1 0 0
1 1 0
Now what I want to do is to insert 0 after each 0 and 1 after each 1. So the result would be
0 0 1 1 0 0
1 1 0 0 0 0
1 1 1 1 0 0
I tried looping through the array, but since length of binary array is still 3, I can't loop through each element.
Can anyone please help me with this?
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Akzeptierte Antwort
Stephen23
am 25 Mär. 2021
The MATLAB approach:
arr = [2,4,6];
mat = repelem(de2bi(arr,'left-msb'),1,2)
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Weitere Antworten (2)
David Goodmanson
am 25 Mär. 2021
Bearbeitet: David Goodmanson
am 25 Mär. 2021
Hi Neeraj,
not having the communications toolbox I used dec2bin instead, which gives a character array but it is basically the same idea and should work on a binary array I would think.
arr = [2,4,6];
a = dec2bin(arr)
s1 = size(a,1);
s2 = size(a,2);
c(1:s1,1:2:2*s2) = a;
c(1:s1,2:2:2*s2) = a
2 Kommentare
David Goodmanson
am 26 Mär. 2021
Hi Neeraj,
The index 1 : 2*s2 is twice as large as the number of columns in 'a'.
In the first step, by using 1:2:2*s2, 'a' is inserted into the odd numbered columns of the new matrix.
In the 2nd step, by using 2:2:2*s2, 'a' is inserted into the even numbered columns of the new matrix.
DGM
am 25 Mär. 2021
You should be able to loop through the array regardless of its size. That said, you don't need to.
A=[1 2 3 4];
B=dec2bin(A);
expanded=B(:,round(0.5:0.5:size(B,2)));
which gives:
expanded =
000011
001100
001111
110000
2 Kommentare
DGM
am 26 Mär. 2021
Bearbeitet: DGM
am 26 Mär. 2021
This bit:
0.5:0.5:size(B,2)
generates a vector like so:
[0.5 1.0 1.5 2.0 2.5 3.0 ... ]
rounding that vector gives us this:
[1 1 2 2 3 3 ... ]
so that we're referencing each element of B twice
Alternatively, you could use something like kron() to generate the same index vector:
kron([1 2 3 4],[1 1])
would yield
[1 1 2 2 3 3 4 4 ]
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