Performing Action to ALL 'struct' Variables

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Philip
Philip on 19 May 2011
Edited: per isakson on 25 Feb 2018
Is there a way to perform the same action on several variables of type 'struct'?
In my case, I have 30 separate 'struct' variables (with non-logical names), and each of them contains a single vector of 200 elements. I only want to deal with the second half of these elements so I need something like:
struct_name = struct_name.data(100:end)
But need to keep the name of the struct variable intact. Does anyone have any suggestions?
I hope this made sense!

Accepted Answer

Matt Fig
Matt Fig on 19 May 2011
% Create several structures with different names...
structn.dat = 1:10;
structm.dat = 1:10;
structk.dat = 1:10;
% Now edit the data.
save mystructs structn structm structk
X = load('mystructs');
F = fieldnames(X);
for ii = 1:length(F)
X.(F{ii}).dat = X.(F{ii}).dat(5:10);
end
% Check
X.structm.dat
  8 Comments
Walter Roberson
Walter Roberson on 19 May 2011
SFN = fieldnames(MyStruct);
for K = 1 : length(SFN)
var_name = SFN{K};
VFN = fieldnames(MyStruct.(var_name));
for N = 1 : length(VFN)
this_field = VFN{N};
if isvector(MyStruct.(var_name).(this_field)) & ...
length(MyStruct.(var_name).(this_field)) > 100
MyStruct.(var_name).(this_field) = MyStruct.(var_name).(this_field)(1:100);
end
end
end

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More Answers (1)

Fangjun Jiang
Fangjun Jiang on 19 May 2011
Would this help?
a(200).b=1;
a(200).c=0;
NewStruct=a(100:end);
Or, Do you mean keep the struct variable name, not the field names:
a(1:99)=[];
Now I think you mean this:
a.Data=1:200;
a.Data(1:100)=[]
  1 Comment
Philip
Philip on 19 May 2011
Apologies - I feared I wasn't very clear.
I meant to say that I have 30 separate variables (of type 'struct'), and each of these has a different name (i.e. fh, cy, de, it etc..). Now, instead of each of them containing 200 elements, I want to 'update' each of them so that they each contain only the last 100.

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