Problem calculating haversine. Obtained distance is too big
    8 Ansichten (letzte 30 Tage)
  
       Ältere Kommentare anzeigen
    
    Jaime De La Mota Sanchis
 am 13 Mär. 2021
  
    
    
    
    
    Beantwortet: Jaime De La Mota Sanchis
 am 14 Mär. 2021
            Hello everyone. I am working in airplane conflic detection. I have two aircraft optimized routes and I need to know the distance between them. The trajectories are given in degrees. I have tried to use the haversine  to calculate the distance between each trajectory points as
RT=6378*1000;
haversine_angle=(sin((meanPhi2-meanPhi1)/2)).^2+cos(meanPhi1).*cos(meanPhi2).*(sin((meanLam2-meanLam1)/2)).^2;
haversine_sqrt=(haversine_angle).^0.5;
haversine_mean_distance_alternative =RT.*asin(haversine_sqrt);
figure
plot(meanTim2, haversine_mean_distance_alternative, 'b')
When I execute the code, I obtain the results displayed in figure 1. 

However, if I calculate the distance between the starting points, it is way smaller that the one displayed in the figure 1. 

I don't know what I am doing wrong in my calculation. As far as I see, I have implemented everything well. Also, note that if I use radians in the angles as 
meanLam1=deg2rad(meanLam1);
meanLam2=deg2rad(meanLam2);
meanPhi1=deg2rad(meanPhi1);
meanPhi2=deg2rad(meanPhi2);
The distance is 

Which still doesn't look like the one in the map.
Can someone help me?
Regards.
Jaime.
I am also attaching the files which contain the trajectories of both airplanes and the time (which is the same for both airplanes)
0 Kommentare
Antworten (1)
Siehe auch
Kategorien
				Mehr zu Quadcopters and Drones finden Sie in Help Center und File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
