question about matrix interleavers??

how to interleave a matrix and deinterleave it?? so it gets back to its original state?

3 Kommentare

the cyclist
the cyclist am 26 Mai 2013
I suggest you give more detail and/or a small example of what you mean. I, for one, don't understand specifically what you mean by "interleave".
mary
mary am 26 Mai 2013
interleaver: it rearrange or reshape the matrix deinterleaver : it restores the original arrangement of the maatrix
Image Analyst
Image Analyst am 26 Mai 2013
That's no answer.

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Azzi Abdelmalek
Azzi Abdelmalek am 26 Mai 2013

0 Stimmen

you can use reshape function. give an example of matrices you want to interleave

9 Kommentare

mary
mary am 26 Mai 2013
i don't know how do interleavers work. i only know how to implement matrix transpose..
could you give any example about any type of interleavers?
% Example
A=[1 2 0;3 4 0;5 6 0];
B=10*A+100
% the code
Result=reshape([A(:) B(:)]',2*size(A,1), [])
Image Analyst
Image Analyst am 26 Mai 2013
mary, do your matrices all have the same number of rows and columns? Do you want to interleave by rows or by columns? Please give an example of the most general case.
mary
mary am 26 Mai 2013
it has the same number of rows and columns, and i want to interleave by rows.
the only case i know is:
a=[1 1 1;2 2 2;3 3 3];
after being interleaved will be:[1 2 3;1 2 3;1 2 3]
This is transposition
out=a'
mary
mary am 26 Mai 2013
and i only have one matrix that i want to change its order. i dont want to combine 2 matrices.
Azzi Abdelmalek
Azzi Abdelmalek am 26 Mai 2013
How do you want to change it?
There are many function to change your matrix
flipud
fliplr
rot90
circshift
mary
mary am 26 Mai 2013
i will try these .. thank you indeed

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Image Analyst
Image Analyst am 26 Mai 2013

0 Stimmen

Not sure what you mean, but here's one way/interpretation:
m1 = magic(6)
m2 = ones(10, 6)
columns = size(m1, 2)
m1Rows = size(m1, 1)
m2Rows = size(m2, 1)
m3 = zeros(m1Rows+m2Rows, columns);
% Interleave. If there's any difference in the number of rows,
% the mismatching rows will be zero.
% You could handle that differently if you want to,
% for example, just append the remaining rows
% of the taller array.
for row = 1 : max([m1Rows, m2Rows])
m3Row = 2 * (row-1)+1;
if row <= m1Rows
m3(m3Row, :) = m1(row, :);
end
if row <= m2Rows
m3(m3Row+1, :) = m2(row, :);
end
end
m3

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